在一个TextView单击时在浏览器中打开链接之前打开一个弹出/警报 [英] Open a popup/alert before opening a link in the browser when clicked on a textview

问题描述

我用 Html.fromHtml（串）数据填充到TextView中。
通过设置 textview.setMovementMethod（LinkMovementMethod.getInstance（））来TextView的，它会打开在浏览器中提供的数据自动的任何链接。但是，我想打开一个弹出窗口，使用户可以选择继续打开链接或取消该过程。

I'm using Html.fromHtml(string) to populate data into textview. By setting the textview.setMovementMethod(LinkMovementMethod.getInstance()) to the textview, it opens any links provided in the data automatically in the browser. But, I want to open a popup giving the user the option to continue with opening the link or cancel the process.

推荐答案

您可以编写下面code：

You can write the below code:

textView.setOnClickListener(new OnClickListener(){

    Builder builder = new AlertDialog.Builder(context);
    AlertDialog alert = builder.create();
    alert.setButton(AlertDialog.BUTTON_POSITIVE, "OK",new DialogInterface.OnClickListener() {
        public void onClick(DialogInterface dialog, int which) {

            //YOUR CODE TO OPEN LINK IN WEBVIEW

            alert.dismiss();
        }
    });

    alert.setButton(AlertDialog.BUTTON_NEGATIVE, "Cancel",new DialogInterface.OnClickListener() {
        public void onClick(DialogInterface dialog, int which) {
            alert.dismiss();
        }
    });
    alert.setTitle("ANY TITLE");
    alert.setMessage("ANY MESSAGE");

    alert.show();
});

希望它会帮助你。

Hope it will help you.

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