如何以克隆形式(javascript)重命名所有ID? [英] How to rename all id in a cloned form (javascript)?

问题描述

我有一个以这种方式克隆的表单(commonStuff)(还有一个在jquery mobile中设计的html页面，该表单多次出现，已被克隆):

I have a form (commonStuff) cloned this way (and an html page, designed in jquery mobile, where the form appears multiple times, cloned):

var commonClone = commonStuff.cloneNode(true);

和此功能

function renameNodes(node) {
    var i;
    if (node.length) {
        for (i = 0; i < node.length; i += 1) {
            renameNodes(node[i]);
        }
    } else {
        // rename any form-related elements
        if (typeof node.form !== 'undefined') {
           node.id = currentPrefix + '_' + node.id;
           node.name = currentPrefix + '_' + node.name;

        // This assumes that form elements do not have child form elements!
        } else if (node.children) {
            renameNodes(node.children);
        }
    }
}

在ID和表单中任何元素的名称之前添加前缀"form1 _"，"form_2"(当前前缀)，并应用于commonClone(并递归应用于其儿子).

which add a prefix 'form1_', 'form_2' (the currentPrefix) to id and names of any element in the form and is applied to commonClone (and so recursively to his sons).

renameNodes(commonClone);

在像文本输入这样的情况下，它可以完美工作

It work perfectly in case of text inputs like

    <div data-role="fieldcontain" class="ui-field-contain ui-body ui-br">
        <label for="foo" class="ui-input-text">Age:</label>
        <input type="text" name="age" id="age" value="" class="ui-input-text ui-body-c ui-corner-all ui-shadow-inset">
    </div>

但是在单选按钮之类的失败

But it fails on radio buttons like

  <div data-role="fieldcontain">
        <fieldset data-role="controlgroup" data-type="horizontal">
            <legend>Address:</legend>
                <input type="radio" name="radio-address" id="radio-address_female" value="1" checked="checked" />
                <label for="radio-address_female">Address 1</label>

                <input type="radio" name="radio-address" id="radio-address_male" value="2"  />
                <label for="radio-address_male">Address 2</label>
        </fieldset>
    </div>

将重命名应用于"fieldcontain"和"controlgroup"之类的外部div.如果我删除了这两个divs，但是图形效果是不可接受的...

applying the renaming to the outer divs like 'fieldcontain' and 'controlgroup'. It works if i remove those two divs but the graphical effect is unacceptable...

就目前而言，我知道问题出在最后一个"else if"块中，因为它不在乎兄弟姐妹，但我真的不知道如何解决此问题.有什么主意吗?

As far as now, i got the problem is in the last 'else if' block for it doesn't care of siblings, but I don't really know how to fix this. Any idea?

此代码来自此答案如何创建具有通用div的选项卡式html表单

推荐答案

在使用jQuery mobile时，将可以使用jQuery. 我希望这段代码能为您指明正确的方向:

As you use jQuery mobile, jQuery will be available. I hope this code will point you in the right direction:

var i = 0;
$("form").each(function() {
  $(this).find("input, select").each(function() {
    $(this).attr("id", "form" + i + "_" + $(this).attr("id"));
    $(this).attr("name", "form" + i + "_" + $(this).attr("name"));
  });
  $(this).find("label").each(function() {
    $(this).attr("for", "form" + i + "_" + $(this).attr("for"));
  });
  i++;
});

编辑:

我了解您当前使用标签的方法会失败.考虑将输入元素包装在label标记内.在这种情况下，您将不需要for属性.这符合以下文档: http://api.jquerymobile.com/checkboxradio/ 考虑一下:

I understand your current approach fails with labels. Consider to wrap your input elements inside the label tag. In that case, you won't need the for-attribute. This is in accordance with the docs: http://api.jquerymobile.com/checkboxradio/ Consider this:

HTML

<form>
  <div data-role="fieldcontain">
    <fieldset data-role="controlgroup" data-type="horizontal">
      <legend>Address:</legend>
      <label><input type="radio" name="radio-address" id="radio-address_female" value="1" checked="checked" />Address 1</label>
      <label><input type="radio" name="radio-address" id="radio-address_male" value="2" />Address 2</label>
    </fieldset>
  </div>
  <div data-role="fieldcontain" class="ui-field-contain ui-body ui-br">
    <label><input type="text" name="age" id="age" value="" class="ui-input-text ui-body-c ui-corner-all ui-shadow-inset">Age:</label>
  </div>
</form>

jQuery

var i = 0, currentPrefix = "form";
$("form").each(function() {
  $(this).find("input, select").each(function() {
    $(this).attr("id", currentPrefix + i + "_" + $(this).attr("id"));
    $(this).attr("name", currentPrefix + i + "_" + $(this).attr("name"));
  });
  i++;
});

Workin小提琴: https://jsfiddle.net/EliteSystemer/8sx6rnwo/

Workin fiddle: https://jsfiddle.net/EliteSystemer/8sx6rnwo/

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