如何使用滚动位置检测屏幕中央的哪个元素? [英] How to detect which element is on the center of the screen with scroll position?

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问题描述

我想检测在向下/向上滚动时在屏幕上可见的元素. 我必须在针对该元素的菜单上将其设置为活动菜单项.

I want to detect which element is visible on the screen when scrolling down/up. I have to set as active menu item on the menu which targets that element.

// must have a page class
$('.page').each(function(){
    $positionData[$(this).attr('id')] = $(this).offset().top;
});

$(document).scroll(function(){
    var $position = $(this).scrollTop();
    if($position > $height && !$body.hasClass('scrolled')) {
        $body.addClass('scrolled');

        //detech the scroll is between an element offset
    } else if($position < $height) {
        $body.removeClass('scrolled');
    }
});

有什么主意吗?

推荐答案

对于 Bootstrap 用户;

已经可以找到一个名为Scrollspy的组件.

There is a component already can be found named Scrollspy.

Scrollspy

如何使用?

1:为身体添加相对位置.

1: Add relative positioning to body.

body {
    position: relative;
}

2:将data-spy ="scroll"和data-target ="属性添加到您的身体. (数据目标必须以您的菜单为目标)

2: Add data-spy="scroll" and data-target="" attributes to your body. (data-target must target your menu)

<body data-spy="scroll" data-target="#navbar-example">

3:设置菜单.请勿将Nav类添加到您的ul/ol元素中.

3: Set your menu. Don't for get to add nav class to your ul/ol element.

<div id="navbar-example">
    <ul class="nav">
        <li><a href="#home">HOME</a></li>
        <li><a href="#project">PROJECT</a></li>
    </ul>
</div>

4:检查目标元素,每个元素必须具有与链接目标相同的id属性.

4: Check your target elements to every element must have an id attribute same as your link targets.

<div id="home"></div>

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