$ .getJson> $ .each返回未定义 [英] $.getJson> $.each returns undefined
本文介绍了$ .getJson> $ .each返回未定义的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
function getData(d){
Back = new Object();
$.getJSON('../do.php?',
function(response){
if(response.type == 'success'){
Back = { "type" : "success", "content" : "" };
$.each(response.data, function(data){
Back.content +='<div class="article"><h5>'+data.title+'</h5>'
Back.content +='<div class="article-content">'+data.content+'</div></div>';
});
}
else{
Back = {"type" : "error" };
}
return Back;
});
}
console.log(getData());
返回未定义!为什么?
推荐答案
您不能以同步方式调用异步函数.在您的代码中,这是
You can't call an asynchronous function in a synchronous way. In your code, this:
function(response){
if(response.type == 'success'){
Back = { "type" : "success", "content" : "" };
$.each(response.data, function(data){
Back.content +='<div class="article"><h5>'+data.title+'</h5>'
Back.content +='<div class="article-content">'+data.content+'</div></div>';
});
}
else{
Back = {"type" : "error" };
}
return Back;
}
在此之后运行:console.log(getData());
$.getJSON
中的回调(第二个参数)在服务器返回响应后立即运行,但不会立即发生.
The callback (second parameter) in $.getJSON
runs once the server returns a response, this doesn't happen instantly.
如果在实际运行时调用日志记录,您将获得预期的结果:
If you call the logging when it actually runs like this, you will get the expected results:
Back = new Object();
$.getJSON('../do.php?', function(response) {
if(response.type == 'success') {
Back = { "type" : "success", "content" : "" };
$.each(response.data, function(data) {
Back.content +='<div class="article"><h5>'+data.title+'</h5>';
Back.content +='<div class="article-content">'+data.content+'</div></div>';
});
} else {
Back = {"type" : "error" };
}
console.log(Back);
});
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