Javascript模块模式，ajax函数回调 [英] Javascript module pattern, ajax functions callbacks

问题描述

var ajaxStuff = (function () {

    var doAjaxStuff = function() {
      //an ajax call
    }

    return {
       doAjaxStuff : doAjaxStuff 
    }

})();

有什么方法可以利用这种模式，并在调用我的方法时从成功的ajaxcall中获取响应?像这样:

Is there any way to make use of this pattern, and fetch the response from a successful ajaxcall when calling my method? Something like this:

ajaxStuff.doAjaxStuff(successHandler(data){
    //data should contain the object fetched by ajax
});

希望您能明白，否则我会详细说明.

Hope you get the idea, otherwise I'll elaborate.

推荐答案

两件事: 1.将参数添加到doAjaxStuff函数. 2.调用doAjaxStuff时，传入一个匿名函数(或函数名称)

Two things: 1. Add a parameter to the doAjaxStuff function. 2. When invoking doAjaxStuff, pass in an anonymous function (or the name of a function)

var ajaxSuff = (function () {

var doAjaxStuff = function(callback) {
   // do ajax call, then:
   callback(dataFromAjaxCall);
}

return {
   doAjaxStuff : doAjaxStuff 
}

})();

// calling it:

ajaxStuff.doAjaxStuff(function(data){
    //data should contain the object fetched by ajax
});

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