与jQuery.extend合并循环:最后一个值始终是相同的吗? [英] Merge loops with jQuery.extend: last value is always the same?

问题描述

我有两个哈希"数组.我需要将它们合并在一起，所以最终结果是另一个哈希数组，但条目数是两个数组的乘积.

I have two arrays of "hashes". I need to merge them together so the end result is another array of hashes, except the number of entries is the product of the two arrays.

    inhabitants = {}
    idx = 0
    for (i=0; i<persons.length; i++) {
        person = persons[i];
        for (j=0; j<houses.length; j++) {
            house = houses[j];
            console.log(house);
            inhabitants[idx] = $.extend(person,house);
            console.log(inhabitants[idx]);
            idx++;
        }
    }

我最终得到的是一个愚蠢的条目，它取决于$ .extend()行中参数的顺序.并且添加的房屋"条目始终是阵列中的最后一个条目.

What I end up with is a silly number of entries that depends on the ordering of the parameters in the $.extend() line. And the "house" entry that is added is ALWAYS THE LAST ENTRY IN THE ARRAY.

很显然，jQuery的$ .extend()并没有达到我的期望.有人可以帮忙吗?

Clearly this $.extend() from jQuery is not doing what I expect. Can anyone help?

推荐答案

$.extend(a, b)将b合并到a，然后返回a.

$.extend(a, b) merges b into a, and returns a.

您正在使用的返回值，但似乎您错过了a也被更改的事实-您当前每次都将相同的变量person分配给inhabitants[idx].

The return value you're using but it seems you were missing the fact that a is also being changed - you're currently assigning the same variable person to inhabitants[idx] each time.

这篇关于与jQuery.extend合并循环:最后一个值始终是相同的吗?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！