呼唤“LS”在Android上使用根返回任何内容，应用程序挂起 [英] Calling 'ls' with root on Android returns nothing, application hangs

问题描述

我有我正在上一个Android应用程序需要根。它使用根访问一些内部记忆的东西，然后我称之为 LS 上的目录。然后，我从它是否有数据，但如果该目录是空的，应用程序只是挂起伟大的工程读取。有没有解决这个好办法？

这里的code

最终运行运行时间=调用Runtime.getRuntime（）;
            尝试{
                //执行su到获得root权限
                进程p =的Runtime.exec（苏）;
                DataOutputStream类输出=新的DataOutputStream类（p.getOutputStream（））;
                output.writeBytes（LS+目录路径+\\ n）;
                output.flush（）;
                InputStream的标准输出= p.getInputStream（）;
                字节[]缓冲区=新的字节[1024];
                INT读;
                串出=新的String（）;
                而（真）{
                    //如果LS没有发现文件就挂在这条线
                    读= stdout.read（缓冲）;
                    OUT + =新的String（缓冲，0，读）;
                    如果（读＆LT; 1024）{
                        打破;
                    }
                }
            }


解决方案

对我来说，以下工作：
看到我的<一个href=\"https://bitbucket.org/jholetzeck/ministatus-android/src/0d594b5dbe0f9c838c4a61cb0e339f1ae11cb883/src/de/holetzeck/util/ProcessHelper.java?at=default\"相对=nofollow>过程帮手再例如：

 对＆LT;整数，字符串＆GT; RET = ProcessHelper.runCmd（真实的，苏，-c，ls -l命令）;
 

I have an Android application that I'm working on that requires root. It uses root to access some of the internal memory stuff, and then I call ls on a directory. I then read from it which works great if there is data, but if the directory is empty, the application just hangs. Is there a good way around this?

Here's the code

    final Runtime runtime = Runtime.getRuntime();
            try {
                // Perform su to get root privileges
                Process p = runtime.exec("su");
                DataOutputStream output = new DataOutputStream(p.getOutputStream());
                output.writeBytes("ls " + directoryPath + "\n");
                output.flush();
                InputStream stdout = p.getInputStream();
                byte[] buffer = new byte[1024];
                int read;
                String out = new String();
                while(true){
                    //If ls found no files it hangs on this line
                    read = stdout.read(buffer);
                    out += new String(buffer, 0, read);
                    if(read < 1024){
                        break;
                    }
                }
            }

解决方案

The following works for me: see my process helper and then for example

Pair<Integer, String> ret = ProcessHelper.runCmd(true, "su", "-c", "ls -l");

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