自动前进输入字段(多部分序列号) [英] Auto advance input fields (multi-part serial number)

问题描述

我正在尝试构建一个由4部分组成的序列号输入，该输入会针对序列号的每个块自动进行调整.

I'm trying to build a 4-part serial number input that auto-advances for each chunk of the serial number.

例如1-384-3884-39

e.g. 1-384-3884-39

此外，我如何在提交时将字符串加在一起成为一个字符串?

Also, how would I add the strings together into one string on submit?

推荐答案

我为您做了小提琴 http://jsfiddle.net/fLz4LL9g/3/

表格:

<form>
    <input id="i1" class="i" type="number" value="">-
    <input id="i2" class="i" type="number">-
    <input id="i3" class="i" type="number">-
    <input id="i4" class="i" type="number">
</form>

代码:

var digitsPerBox = 4;

/// EACH INPUT
$(".i").on("input",function(e) {

    if (e.target.value.length == digitsPerBox) {
        var t = $( e.target );
        if (t.attr("id") == "i4") {
            /// SUBMIT HERE
            var txt = $("#i1").val() + "-" + $("#i2").val() + "-" + $("#i3").val() + "-" + $("#i4").val();
            alert(txt);
        } else {
            /// AUTO FOCUS NEXT BOX
            t.next().focus();
       }
    }
    /// LIMIT DIGITS PER BOX
    if (e.target.value.length > digitsPerBox) {
        e.target.value = e.target.value.substr(0,digitsPerBox);
    }


///// ONLY NUMBER ALLOWED    
}).keydown(function (e) {
        // Allow: backspace, delete, tab, escape, enter and .
        if ($.inArray(e.keyCode, [46, 8, 9, 27, 13, 110, 190]) !== -1 ||
             // Allow: Ctrl+A
            (e.keyCode == 65 && e.ctrlKey === true) || 
             // Allow: home, end, left, right
            (e.keyCode >= 35 && e.keyCode <= 39)) {
                 // let it happen, don't do anything
                 return;
        }
        // Ensure that it is a number and stop the keypress
        if ((e.shiftKey || (e.keyCode < 48 || e.keyCode > 57)) &&                 (e.keyCode < 96 || e.keyCode > 105)) {
            e.preventDefault();
        }
});

这篇关于自动前进输入字段(多部分序列号)的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！