避免D3.js中的子节点重叠 [英] Avoid overlapping of child nodes in D3.js

问题描述

我正在使用D3.js构建一个显示Facebook用户及其Facebook朋友的树形结构.根是用户，子节点是朋友.我的UI宽度固定，问题是子节点会相互重叠.

I am building a tree structure showing the Facebook user and his/her Facebook friends using D3.js. The root is the user and the child nodes are the friends. I have a fixed width in my UI and the problem is the child nodes will overlap to each other.

              var nodes = tree.nodes(root).reverse(),
               links = tree.links(nodes);

              nodes.forEach(function(d) { d.y = d.depth * 130; });

              var node = svg.selectAll("g.node")
               .data(nodes, function(d) { return d.id || (d.id = ++i); });

              var nodeEnter = node.enter().append("g")
               .attr("class", "node")
               .attr("value", function(d){
                return d.id; })
               .attr("transform", function(d) { 
                return "translate(" + d.x + "," + d.y + ")"; });

              var defs = node.append("defs").attr("id", "imgdefs");

              var imgPattern = defs.append("pattern")
                    .attr("id", "img")
                    .attr("height", 50)
                    .attr("width", 50)
                    .attr("x", "0")
                    .attr("y", "0");


                imgPattern.append("image")
                     .attr("height", 60)
                     .attr("width", 60)
                     .attr("xlink:href", function(d) { return d.img; });

                nodeEnter.append("circle")
                    .attr("r", 30)
                    .style("stroke","white")
                    .style("stroke-width", 4)
                    .attr("fill", "url(#img)");

我想为子节点每行/深度显示10个朋友.任何帮助或建议，请.谢谢！

I would like to display 10 friends per row/depth for the child nodes. Any help or suggestions please. Thank you!

这是我的jsfiddle:在此处编码

Here is my jsfiddle: CODE HERE

推荐答案

一种方法是设置nodeSize和separation属性/d3/wiki/Tree-Layout"rel =" nofollow noreferrer>树状布局.这是代码段:

One way to accomplish this is to set the nodeSize and separation properties of the tree layout. Here is the snippet:

var tree = d3.layout.tree()
    //.size([height, width])
    .nodeSize([30,])
    .separation(function separation(a, b) {
        return a.parent == b.parent ? 2 : 1;
    });

我将nodeSize属性的x尺寸设置为等于圆的半径.

I set the x dimension of the nodeSize property equal to the radius of the circles.

此外，必须更改g转换以重新定位图表:

Also, a change in the g transform is necessary to reposition the chart:

.attr("transform", "translate(" + (margin.left + width/2) + "," + margin.top + ")");

您可以放心地忽略size属性(请参阅上面链接中的文档以及此

You can safely ignore the size property (see documentation in the link above and this SO answer).

这是一个 FIDDLE .我添加了另一排不同深度的圆圈，以检查该解决方案是否足够可靠.我认为这应该可以帮助您.

Here is a FIDDLE with the changes. I added another row of circles at a different depth to check whether the solution was robust enough. I think this should get you going.

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