使用jQuery检索chid div的id? [英] Retrieving ids of chid divs using jquery?

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本文介绍了使用jQuery检索chid div的id?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

请查看下面的代码.

                <div id="click_me">Save</div> 


<div id="blocks_sortable">
    <div id="block_1">
        <h2>Block 1</h2>

        <div class="items_sortable connectedSortable">
            <div id="item_1"> 
                <span>Item 1</span></div>   
            <div id="item_2"> 
                <span>Item 2</span></div>
            <div id="item_3"> 
                <span>Item 3</span></div>
        </div>
    </div>  
    <div id="block_2">
        <h2>Block 2</h2>

        <div class="items_sortable connectedSortable">
            <div id="item_4"> 
                <span>Item 4</span></div>   
            <div id="item_5"> 
                <span>Item 5</span></div>
            <div id="item_6"> 
                <span>Item 6</span></div>
        </div>
    </div>
</div>

<script>
    $("#click_me").click(function() {
            var result = $("#blocks_sortable > div");

            for(var i=0; i<result.length; i++){
                var str = ""; 
                var str2 = "";
                var block = result[i]; //div object

                //retrieve block id and create the string with id
                str += "block="+$(block).attr("id")+"&items=";

                //trying to select all the items of the current Block
                var result2 = $(block+" > div");                        
                    for(var j=0; j<result2.length; j++){
                        var item = result2[j];

                        str2 += $(item).attr("id")+",";
                    } //end for items

                str = str+str2;
                // looking for a final string in the format of .. block=block_1&items=item_1,item_2,item_3 for loop 1
                alert(str);
            }
    });
</script>

它不起作用.有没有更简单且可行的解决方案来获取这些ID.请帮忙.

It is not working. Is there any easier and working solution to get these ids. Please help.

谢谢.

推荐答案

jQuery映射功能是你的朋友

$.map( 
    $("#blocks_sortable > div"),
    function(elementOfArray){
        var block = $(elementOfArray);
        var children = $.map(
            $("div[id]", block),
            function( eoa ){
                return eoa.id;
            }).join(",");

        return elementOfArray.id + "=" + children;
    }
).join(",");

将返回"block_1=item_1,item_2,item_3,block_2=item_4,item_5,item_6",它将使您更接近要去的地方(我认为).

Will return "block_1=item_1,item_2,item_3,block_2=item_4,item_5,item_6", which gets you much closer to where you're going (I think).

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