有没有一种方法可以从JQuery Ajax调用返回值(在我的情况下为xml) [英] Is there a way to return a value (xml in my case) from a JQuery Ajax Call

问题描述

我想我缺少一些非常基本的东西，也许有人可以填补我的空白.我从两个地方使用过ajax调用.因此，现在我试图通过使调用返回一个值来重用该调用.看起来像这样:

I guess I am missing something quite fundamental and maybe someone can fill me in. I have used an ajax call from two places. So now I am trying to reuse that call by making the call return a value. It looks something like this:

function getInfo()
{
    $.ajax({
    type: "GET",
    url: "../ajax.aspx?action=getInfo&id=4", 
        dataType: "xml",
    async: false,
    error: function() {
        alert("Something went wrong.");
    }, 
    success: function(xml) {
            // Do some extra work here
    $(xml).find("room").each(function() {
        // Do something based on the xml
    }); 
    // Something else can use this XML so return it too.
            // Why does this return not work???
            return xml;
    } 
});
}

所以我在脚本的其他地方调用了该函数

So somewhere else in the script i am calling that function

var xml = getInfo();
// Try do something with it now but it says that it is undefined

当我说它是不确定的时，我是在谈论Firebug.

and when i say it says it is undefined I am talking about Firebug.

推荐答案

关闭异步功能并不是一种很好的AJAX编程风格.您将失去这项技术的许多优点. 从jquery文档中:

Turning off the asynchronous functionality is imho not a very good AJAX programming style. You will loose a lot of the advantages of this technology. From the jquery documentation:

请注意，同步请求可能会 暂时锁定浏览器， 禁用任何操作，而 请求处于活动状态.

Note that synchronous requests may temporarily lock the browser, disabling any actions while the request is active.

如果仍然需要这样做: $ .ajax返回它创建的XMLHTTPRequest对象.并且您的getInfo方法也应该返回该值，因此您的代码应按如下所示进行修改:

If you need to do it anyway: $.ajax returns the XMLHTTPRequest object it creates. And your getInfo method should return that as well, so your code should be modified like this:

function getInfo()
{
    return $.ajax({
    type: "GET",
    url: "../ajax.aspx?action=getInfo&id=4", 
        dataType: "xml",
    async: false,
    error: function() {
        alert("Something went wrong.");
    }, 
    success: function(xml) {
            // Do some extra work here
        $(xml).find("room").each(function() {
            // Do something based on the xml
        });     
        // Something else can use this XML so return it too.
            // Why does this return not work???
            return xml;
    } 
}).responseText;
}


var xml = getInfo();

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