jQuery到PHP的数据传输 [英] jQuery to PHP data transfer
本文介绍了jQuery到PHP的数据传输的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
具有以下jQuery文件
Having following jQuery file
$( document ).ready(function() {
var urlform = "register/ajax";
$("#btnRegister").click( function() {
$("#Register").submit( function() {
return false;
});
$.ajax({
url: urlform,
type: 'POST',
dataType: 'json',
async: true,
data: $("#Register").serialize(),
success: function (data) {
$("#email").css("border-color", "green");
$("#rCheck").text(data);
console.log(data);
},
error: function (data) {
$("#email").css("border-color", "red");
$("#rCheck").text(data);
console.log(data);
}
});
});
});
在控制台日志中,我得到
In console log i get
Object {email_reg: Object, confirm_password_reg: Object}
confirm_password_reg: Object
notSame: "Passwords Doesn't Match"
__proto__: Object
email_reg: Object
recordFound: "E-mail address already exists"
__proto__: Object
__proto__: Object
要获得更清晰的解释,请访问以下链接:.
For more clear interpretation there is following link:.
但是当使用 $(#rCheck").text(data); 在div中传输数据时,它仅获得 [object Object] .
But when transfering data in div using $("#rCheck").text(data); it gets only [object Object].
问题:如何仅传输以下错误消息:
Problem How to transfer only error messages like:
- 密码不匹配
- 电子邮件地址已存在
Json编码
if (!$form->isValid()){
// email is invalid; print the reasons
$json= $form->getMessages();
$response->setContent(\Zend\Json\Json::encode($json));
}
return $response;
在这里如何将$ json插入数组中.
How here $json can be pun in an array.
推荐答案
问题在于data
是一个对象,当传递给.text()
时,该对象将打印其.toString()
版本,即[object Object]
.
the problems is data
is an object, which when passes to .text()
will print its .toString()
version that is [object Object]
.
所以尝试
if (data) {
var msgs = $.map(data, function (fieldObj, key) {
return [$.map(fieldObj, function (msg, key) {
return msg;
})]
});
$('#abc').html(msgs.join('<br />'))
} else {
//do something
}
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