XMLHttpRequest responseText获取完整的源代码 [英] XMLHttpRequest responseText get the full source code

问题描述

我想获取页面的完整源代码，例如www.google.com

I want to get the the full source code of a page e.g. www.google.com

我有一个PHP文件可以复制页面的源代码:

I got a PHP file to copy the source code of a page:

<?php
    echo file_get_contents('http://www.google.com');
?>

我获取源代码的功能:

function sendRequest() {
 var xmlhttp;
 if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari
     xmlhttp = new XMLHttpRequest();
    }
 else {// code for IE6, IE5
     xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
 }

 xmlhttp.onreadystatechange=function(){
    if (xmlhttp.readyState==4 && xmlhttp.status==200){
         var source_code = xmlhttp.responseText;
         alert(source_code);
         var element = $(source_code).filter("#specificelement").html();
     }
    }
xmlhttp.open("GET","test2.php",true);
xmlhttp.send(); 
}

1)为什么不显示完整的源代码?是否有限制或我做错了什么? 我想在源代码中得到一个特定的元素.

1)Why doesn't it show the full source code? Is there a limit or am I doing something wrong? I want to get a specific element within the source code.

2)如果我能够获得特定的元素，是否可以在src路径中添加一些内容?实际图像在原始页面的外部服务器上.因此，我需要在实际映像之前添加服务器.

2) If I'm able to get the specific element, is there a way to add something to the src path? The actual images are on the external server of the original page. Therefore I need to add the server before the actual image.

现在:<img src="/images/blah.jpg" />

我想要的是:<img src="http://server.com/images/blah.jpg" />

更新:

如果执行此操作，则完整的源代码将显示在文本区域中.

If I do this the full source code is shown in the text area.

document.getElementById("textarea").innerHTML = source_code;

是否可以从此处仅获取特定元素的代码?

Is there a way to get only the code of a specific element from here?

推荐答案

当您通过file_get_contents获取代码时，AJAX请求会插入该代码，因为它是其功能，因此AJAX会插入响应.

When you are getting the code through file_get_contents, the AJAX Request interprate that code, because it's its functionality, AJAX interprate the response.

祝你好运.

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