jQuery-将一个输入框与PHP while循环中的另一个输入框进行比较 [英] jQuery - Checking an input box against another input box in a PHP while loop
问题描述
在编写订单提交页面时，我遇到了一个很大的问题，该页面的目的是为订单提出争议-提供两个字段，但前提是一个字段小于另一个字段.
I have come about quite a problem while programming an order submitting page, the aim of the page is to submit a dispute for an order - providing two fields are filled in, but only if one field is less than another one.
基本上，一个是下拉列表，另一个是纠纷"框，查询如下:
Basically, one is a drop down and the other is a disputes box, the queries are as follows:
如果DisputesTextBox ="和一个下拉框="Please Select ..."
If DisputesTextBox = "" and a drop down box = "Please Select..."
一切都很好-启用了提交按钮
Everything is fine - submit button enabled
如果DisputesTextBox！="和下拉框=请选择..."
If DisputesTextBox != "" and dropdown box = "Please select..."
错误(反之亦然，因此，如果出现争执但dropwn =请选择...)-禁用提交按钮
Error ( and vice versa, so if disputes is populated but dropwn = please select...) - submit button disabled
如果DisputesTextox！="和下拉框="Other"
If DisputesTextox != "" and dropdown box = "Other"
一切都很好-启用了提交按钮
Everything is fine - submit button enabled
如果DisputesTextBox>发货箱
If DisputesTextBox > shippedbox
错误-提交按钮已禁用
<table>
<thead>
<tr><th>Item ID</th><th>Description</th><th>Dispute Quantity</th><th>Shipped Quantity</th><th>Ordered Quantity</th><th>Reason</th></tr>
</thead>
<tbody>
<?php
$data = mysql_query("SELECT * FROM `artran09` WHERE `invno` = '$invoiceno'") or die(mysql_error());
echo "<center>";
$i = -1;
echo "<form action=\"submitdispute.php?invno=".$invoiceno."&ordate=".$placed."\" method=\"POST\" onsubmit=\"return confirm('Are you sure you are ready to dispute your order?');\">";
while ($info = mysql_fetch_array($data)) {
$i += 1;
echo "<tr>";
echo "<td>".$info['item']."</td>";
echo "<td>".$info['descrip']."</td>";
echo "<td><input type=\"text\" input name=".$i." onKeyPress=\"return numbersonly(this, event)\" maxLength=\"3\"></td>";
echo "<td><input type=\"text\" value=".$info['qtyshp']." onKeyPress=\"return numbersonly(this, event)\" maxLength=\"3\" disabled=\"disabled\"></td>";
echo "<td><input type=\"text\" value=".$info['qtyord']." onKeyPress=\"return numbersonly(this, event)\" maxLength=\"3\" disabled=\"disabled\"></td>";
echo "<td><select name = \"reason$i\">";
echo "<option>Please Select...</option>";
echo "<option>Short/Not received</option>";
echo "<option>Damaged Goods</option>";
echo "<option>Product Not Ordered</option>";
echo "</select></td>";
echo "</tr>";
}
?>
</tbody>
</table>
</div>
</div>
<p><input type = "submit" value = "Dispute" name ="Submit">
</form>
谢谢，希望任何人都能提供帮助！
Thanks, hope anyone can help!
为Wolf/任何有帮助的人编辑-此代码的最新内容:
Edited for Wolf/anyone who can help - what's up with this code here:
-我编辑的代码-
function validateSubmit(){
// this will loop through each row in table
// Make sure to include jquery.js
$('tr').each( function() {
// Find first input
var input1 = $(this).find('input').eq(0);
var qty1 = input1.val();
// Find Second input
var input2 = $(this).find('input').eq(1);
var qty2 = input2.val();
// Find third input
var input3 = $(this).find('input').eq(2);
var qty3 = input3.val();
// Find select box
var selectBx = $(this).find('select');
var selectVal = selectBx.val();
// Add your validation code here for the inputs and select
// Return true if all validations are correct
// Else return false
if(qty1 = "" && selectVal = "Please Select...") {
return true;
alert("You have an error somewhere, please check over your quantites.");
break;
}
if (qty1 > qty2) {
return false;
alert("You have an error somewhere, please check over your quantites.");
break;
}
});
}
推荐答案
return true;
alert("You have an error somewhere, please check over your quantites.");
break;
如果调用return，则立即停止当前函数的执行并返回值.这意味着在执行return语句之后什么也没有. alert()将不会运行，因为函数以return true结尾.
If you call return, execution of the current function is halted immediately and the value is returned. This means that nothing after a return statement is executed. The alert() will not run, because the functions ends with the return true.
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