将可复制表单的JSON数据解析为PHP for Mail [英] Parsing Duplicatable Form's JSON data to PHP for Mail
问题描述
我有一个表单，其中存在可重复的字段，并且它会生成以下JSON数据:
I have a form where there are duplicate-able fields and it produces the following JSON data:
{
"mainmember": [
{
"name": "testtest",
"surname": "test",
"id": "8509295266086",
"age": "27",
"gender": "Male",
"townofbirth": "george",
"email": "test@test.com",
"contact": "0112121211",
"passport": "1111111111111",
"postal": "grjiubrwg",
"postal_code": "0010",
"residential": "tytyytyttyytyt",
"residential_code": "4422"
}
],
"dependant1": [
{
"name": "testDUP",
"surname": "testDUP",
"id": "4802235040081",
"age": "64",
"gender": "Male",
"townofbirth": "tehjte",
"cell": "4774811845",
"email": "testDUP",
"passport": "8202255133088",
"relationship": "spouse"
}
],
"dependant2": [
{
"name": "testDUP2",
"surname": "testDUP2",
"id": "1111111111111",
"age": "45",
"gender": "F",
"townofbirth": "knysnasw",
"cell": "0000000000",
"email": "testDUP2",
"passport": "2222222222222",
"relationship": "inlaw"
}
]
}
现在，可重复字段是依赖项，在此JSON中有2个依赖项，但是在重复时，它增加为"dependant3，Dependant4，Dependant5".
now the duplicate-able fields are the dependants, in this JSON there's 2 dependant but on duplication it increases to "dependant3, dependant4, dependant5".
目前，当我提交并发送到PHP时，我可以算出家属:
Currently when i submit and send to PHP i can count the dependants:
<?php
$json = $_POST['parameters'];
$json_string = stripslashes($json);
$data = json_decode($json_string, true);
$datasetCount = count($data); // returns count of array items of any array
echo "<h1>There are $datasetCount Dependants</h1>";
$i = 0;
foreach ($data as $each_dep) {
$i++;
echo "<h2>Dependant $i</h2>";
while (list($key, $value) = each ($each_dep)) {
echo "$key: $value<br />";
}
}
?>
和我正在使用的jQuery send函数:
and the jQuery send function I'm using:
jQuery('#submit').click(function(){
jQuery('div[class*="mainmember"]').each(function(k, v){
mainmember = {};
mainmember['id'] = '';
$(v).find('.id').each(function(){
mainmember['id'] += $(this).val();
});
mainmember['age'] = '';
$(v).find('.age').each(function(){
mainmember['age'] += $(this).val();
});
mainmember['gender'] = $(v).find('.gender').val();
result['mainmember'] = [mainmember];
});
jQuery('div[class*="dependant"]').each(function(k, v){
dep_counter++
dependants = {};
result['dependant'+dep_counter] = [dependants];
dependants['id'] = '';
$(v).find('.id').each(function(){
dependants['id'] += $(this).val();
});
dependants['age'] = '';
$(v).find('.age').each(function(){
dependants['age'] += $(this).val();
});
dependants['gender'] = $(v).find('.gender').val();
});
var jsonData = JSON.stringify(result);
console.log(jsonData);
});
我只是无法获取其他数据，例如姓名，姓氏等. 我需要像这样将其解析为电子邮件:
I just cant get the other data, such as name, surname etc. I need to parse it like this to an email:
主要成员: 详细信息
依存者2: 详细信息
依赖者3: 详细信息
任何帮助我们都感激不尽.
Any Help greatly appreciated.
推荐答案
您的json结构非常痛苦，您似乎正在创建单个对象的数组. 相反，您应该具有对象数组或键引用的单个对象.
Your json structure is quite painful, you seem to be creating arrays of a single object. Instead you should have arrays of objects, or single objects referenced by keys.
理想地，对于您的结构，我认为您应该为依赖对象提供一个对象数组，为主要成员提供一个对象，如下所示:
Ideally for your structure, I think you should have an array of objects for the dependents and a single object for the mainmember, like this:
{
"mainmember": {
"name": "test2",
"id": "1111111111111",
"age": "45",
"gender": "M",
"townofbirth": "knysna",
"email": "tjyrrtjhe",
"contact": "1111111111",
"passport": "5555555555555",
"postal": "yrtjyt",
"postal_code": "1101",
"residential": "tkyutk",
"residential_code": "5555"
},
"dependants": [
{
"name": "dtjtet",
"surname": "grwwr",
"id": "1111222222222",
"age": "48",
"gender": "F",
"townofbirth": "knmysn",
"cell": "0045128588",
"email": "fae@gmail.COM",
"passport": "1212112111111",
"relationship": "spouse"
},
{
"name": "dtjtet2",
"surname": "grwwr2",
"id": "11112222222222",
"age": "44",
"gender": "M",
"townofbirth": "knmysn",
"cell": "0045128588",
"email": "fae@gmail.COM",
"passport": "1212112111111",
"relationship": "spouse"
}
]
}
这样，您就具有一个"mainmember"对象和一组依赖项.
This way you have a single "mainmember" object, and an array of dependents.
然后使用如下所示的php代码，您可以为其打印详细信息:
Then with php code like the following you can print the details for it:
<?php
function printMember($member) {
foreach($member as $key=>$value) {
echo "$key : $value <br />";
}
}
$json = $_POST['parameters'];
$json_string = stripslashes($json);
$data = json_decode($json_string, true);
$depCount = count($data["dependants"]);
echo "<h1>There are $depCount Dependants</h1>";
echo "<h2>Main member data:</h2>";
printMember($data["mainmember"]);
foreach ($data["dependants"] as $index => $dependant) {
echo "<h2>Dependant $index</h2>";
printMember($dependant);
}
要在jquery代码中创建正确的json结构，如下所示:
To create the correct json structure in the jquery code, something like this:
jQuery('#submit').click(function(){
jQuery('div[class*="mainmember"]').each(function(k, v){
mainmember = {};
mainmember['id'] = '';
$(v).find('.id').each(function(){
mainmember['id'] += $(this).val();
});
mainmember['age'] = '';
$(v).find('.age').each(function(){
mainmember['age'] += $(this).val();
});
mainmember['gender'] = $(v).find('.gender').val();
//This is changed: Remove the [] from around the mainmember,
//should be a single object not an array
result['mainmember'] = mainmember;
});
//create the array of dependants
result['dependants'] = [];
jQuery('div[class*="dependant"]').each(function(k, v){
dependant = {};
dependant['id'] = '';
$(v).find('.id').each(function(){
dependant['id'] += $(this).val();
});
dependant['age'] = '';
$(v).find('.age').each(function(){
dependant['age'] += $(this).val();
});
dependant['gender'] = $(v).find('.gender').val();
//add the dependant to the array
result['dependants'].push(dependant);
});
var jsonData = JSON.stringify(result);
console.log(jsonData);
});
这未经测试，但应该可以帮助您继续.您的问题是因为您使用的是单个对象的数组，而不是对象本身.
This is untested but should help you proceed. Your problem is because you are using arrays of single objects instead of the object itself.
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