使用AJAX返回PHP错误处理 [英] Return PHP error handling with AJAX

问题描述

我有一个支持PHP和AJAX的页面，当用户提交我的表单之一时，我检查getData.php脚本中的错误.

I have a page powered with PHP and AJAX, when a user submits one of my forms I check for errors in the getData.php script.

此示例是如果用户使用默认值提交表单，我想知道是否有一种方法可以传回这些错误，或者如果用户提交错误或我需要执行错误，则触发AJAX引发错误在AJAX调用之前进行处理

This example is if the user submits the form with the default value I'm wondering if there is a way to pass back those errors or trigger the AJAX to fire an error if the user commits on or if I need to do error handling before the AJAX call

$('form').on('submit', function (e) {
    e.preventDefault();
    $.ajax({
        type: 'post',
        url: '_ajax/addData.php',
        data: $('form').serialize(),
        success: function () {
            $("input").val('Info Here');
            $("form").hide();
            reloadInfo();
        }
    });
});

PHP

$info = $_POST['info'];

if($info != 'Info Here') {
    $conn = mysqli_connect();
    $query = "INSERT INTO leads VALUES(0, '$companyName', 1, NOW(), 3)";
    $result = mysqli_query($conn, $query) or die ('Error Could Not Query');

    $id = mysqli_insert_id($result);
    header("Location: http://localhost/manage/info.php?id=$id");

    mysqli_close($conn);
} else { 
    echo '<script>alert("Error");/script>'
}

PART 2

推荐答案

Javascript:

Javascript:

success: function (data) {
           if(!data.success) alert(data.errors); // Just for demonstration purposes
            $("input").val(data.errors);
            $("form").hide();
            reloadInfo();
        }

PHP:

header("Content-Type: text/json; charset=utf8");
if($info != 'Info Here') {
    $conn = mysqli_connect();
    $query = "INSERT INTO leads VALUES(0, '$companyName', 1, NOW(), 3)";
    $result = mysqli_query($conn, $query) or die ('Error Could Not Query');

    $id = mysqli_insert_id($result);
    header("Location: http://localhost/manage/info.php?id=$id");

    mysqli_close($conn);
} else { 
    echo json_encode(array("success" => false,"error" => "Some random error happened"));
}

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