如何从PHP中的JavaScript读取发布网址请求 [英] How to read post url request from javascript in PHP
问题描述
我有使用html输入的表单.
然后，我添加了这个javascript(jquery)笔画，以读取和收集表单中的所有值或数据.
I have form with inputs in html.
Then I added this javascript (jquery) stroke to read and collect all value or data from form.
var formData = $("#form").serialize();
当我
console.log(formData);
输出将显示:
calc-ownership = ooo& calc-activity = restaurant& calc-tax = usn& calc-tax-2 =费用& calc-bank =合作伙伴& calc-who-pays =客户& operations_count = 0& calc-命名= slim& documents_count = 0& calc-who-docs = client& staff_count = 0& calc-more％5B％5D = patent& calc-more％5B％5D = alcohol& period =& price =& price_sber =& ; rate-name =& email-to =
calc-ownership=ooo&calc-activity=restaurant&calc-tax=usn&calc-tax-2=charge&calc-bank=partners&calc-who-payments=client&operations_count=0&calc-nomenclature=slim&documents_count=0&calc-who-docs=client&staff_count=0&calc-more%5B%5D=patent&calc-more%5B%5D=alcohol&period=&price=&price_sber=&rate-name=&email-to=
然后我在jquery中找到了称为post的函数
$.post(path, formData, success, "json");
要求看起来像:
do.php?bank = partners
Then I found function in jquery called post
$.post(path, formData, success, "json");
Request look like:
do.php?bank=partners
如您所见，它向我的do.php发出了发布请求.
现在，我如何读取该查询并使用该数据?
As you see it makes post request to my do.php.
Now how I can read this query and work with this data?
我在jquery中发现了与$.post类似的东西.是$.ajax
完整代码:
I found analog to $.post in jquery. It is $.ajax
Full code:
$.ajax({ url: path, method: "POST", data: {formData: formData} });
效果很好.
但是我想和$.post
It works well.
But I want to work with $.post
此刻我正在查看自己的网址.它看起来是:https://stackoverflow.com?ask=32321
I am looking at my url at the moment. And it looks : https://stackoverflow.com?ask=32321
我需要类似的内容才能使用php从javascript这个网址读取我的查询
I need something similar to read my query from javascript this url with php
推荐答案
好的，我会举例说明，
如果要获取要使用的url参数值，
If you want to get url parameter values to you have to use,
<script>
let my_variable='<?php echo $_GET['url_param_name'];?>';
</script>
以上以获得更多帮助和理解.现在您想将表单数据发送到php进行处理，因为我得到了您的答案.
above for more help and understanding. Now you want to send form data to php for processing as I got your answer.
这是示例表格.
<form id="my_form" name"my_form" method="POST" onsubmit="return send();">
First name:<br>
<input type="text" name="first_name" value="Mickey">
<br>
Last name:<br>
<input type="text" name="last_name" value="Mouse">
<br><br>
<input type="submit" value="Submit">
</form>
要发布上述表格，我将使用javascript函数，
To post above form I will use javascript function,
<script>
function send() {
$.ajax
({
type: 'POST',
url: './path/your_php_file_where_form_data_processed.php',
data:$('#my_form').serialize(),
success: function () {
// do what you need to do on succeess
},
error: function (x, e) {
// for error handling
if (x.status == 0) {
console.log('You are offline!! - Please Check Your Network.');
} else if (x.status == 404) {
console.log('Requested URL not found.');
} else if (x.status == 500) {
console.log('Internal Server Error.');
} else if (e == 'parsererror') {
console.log('Error. - Parsing JSON Request failed.');
} else if (e == 'timeout') {
console.log('Request Time out.');
} else {
console.log('Unknown Error. - ' + x.responseText);
}
}
});
return false;
}
</<script>
现在，您需要仔细检查表单元素名称.在php文件中.我们来看一下.
Now you need to check carefully your form element names. In php file. Let's look it.
<?php
//include_once './../../classes/Database.php'; import if you have database configurations
//session_start(); make sure to use sessions if your site using sessions
if(isset($_POST))
{
var_dump($_POST); //this will echo your form inputed data.
//if you want use one by one posted data
echo $_POST['first_name'];
echo $_POST['last_name'];
}
else
{
echo 'Data not comes here';
}
?>
这样可以帮助您完成任务.
Thought this might help your task.
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