$ .ajax不是函数 [英] $.ajax is not a function

问题描述

我正在尝试使用 Wunderground Weather API ，但是我在请求按钮单击信息时遇到了麻烦. 这是提供的工作开始线:

Hi i am trying to use Wunderground Weather API but i am having troubles with requesting the information on a button click. Here is the working opening line Supplied:

jQuery(document).ready(function($) {

这就是我将其更改为:

jQuery('#GetWeather').click(function($) {

当我单击按钮时，出现萤火虫错误:

When i click the button i get a firebug Error:

TypeError: $.ajax is not a function
[Break On This Error]   

success : function(parsed_json) {

我不知道为什么它不起作用，但是这里是其余的代码...希望对您有所帮助:

I don't know why it wont work but here is the rest of the code... Hope it helps:

jQuery('#GetWeather').click(function($) {
var PostCode="PL9 9UT";
$.ajax({ url : "http://api.wunderground.com/api/2508132ae0c7601a/geolookup/conditions/q/UK/"+PostCode +".json",
dataType : "jsonp",
success : function(parsed_json) {

var icon = parsed_json['current_observation']['icon'];
var temp_c = parsed_json['current_observation']['temp_c'];
var feelslike_c = parsed_json['current_observation']['feelslike_c'];
var visibility_mi = parsed_json['current_observation']['visibility_mi'];
var UV = parsed_json['current_observation']['UV'];
var relative_humidity = parsed_json['current_observation']['relative_humidity'];
var wind_mph = parsed_json['current_observation']['wind_mph'];
var pressure_mb = parsed_json['current_observation']['pressure_mb'];
var wind_string = parsed_json['current_observation']['wind_string'];
var weather = parsed_json['current_observation']['weather'];

var imageurl = "http://192.168.0.4/DesktopVersion/Inc/Images/Weather/";

$('.Wicon').css('background-image',"url("+imageurl +icon +".svg)");
$('#GetWeatherTemp').html(temp_c +"&#176");
$('#GetWeatherFeel').html("Feels Like " +feelslike_c +"&#8451");
$('#GetWeatherVis').html(visibility_mi +" Miles");
$('#GetWeatherUv').html(UV);
$('#GetWeatherHumid').html(relative_humidity +"%");
$('#GetWeatherWind').html("Wind Speed " +wind_mph +"Mph");
$('#GetWeatherPress').html(pressure_mb);
$('#GetWeatherState').html(weather);
}
});
});

推荐答案

click事件不发送jQuery对象作为参数，而是发送event对象，因此函数内部的$ t是jQuery对象，它将是click事件的event对象.

The click event doesn't send the jQuery object as parameter, it sends the event object, so the $ inside the function won't be the jQuery object, it will be the event object for the click event.

只需删除$参数，以使其不会遮盖全局$标识符:

Just remove the $ parameter so that it doesn't shadow the global $ identifier:

jQuery('#GetWeather').click(function() {

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