在JSF中按ID查找组件 [英] Find component by ID in JSF

问题描述

我想通过提供的ID从托管bean中找到一些UIComponent.

I want to find some UIComponent from managed bean by the id that I have provided.

我写了以下代码:

private UIComponent getUIComponent(String id) {  
      return FacesContext.getCurrentInstance().getViewRoot().findComponent(id) ;  
}

我将p:inputTextarea定义为:

<p:inputTextarea id="activityDescription" value="#{adminController.activityDTO.activityDescription}" required="true" maxlength="120"
    autoResize="true" counter="counter" counterTemplate="{0} characters remaining." cols="80" rows="2" />

现在，如果以getUIComponent("activityDescription")的方式调用该方法，则返回null，但是如果以getUIComponent("adminTabView:activityForm:activityDescription")的方式调用它，则可以获取org.primefaces.component.inputtextarea.InputTextarea实例.

Now if a call to the method as getUIComponent("activityDescription") it is returning null, but if I call it as getUIComponent("adminTabView:activityForm:activityDescription") then I can get the org.primefaces.component.inputtextarea.InputTextarea instance.

是否有任何方法可以获取仅具有ID(即"activityDescription")而不是绝对ID(即"adminTabView:activityForm:activityDescription")的组件?

Is there any way to get the component with only the id i.e., "activityDescription" not the absolute id i.e., "adminTabView:activityForm:activityDescription"?

推荐答案

您可以使用以下代码:

public UIComponent findComponent(final String id) {

    FacesContext context = FacesContext.getCurrentInstance(); 
    UIViewRoot root = context.getViewRoot();
    final UIComponent[] found = new UIComponent[1];

    root.visitTree(new FullVisitContext(context), new VisitCallback() {     
        @Override
        public VisitResult visit(VisitContext context, UIComponent component) {
            if (component != null 
                && component.getId() != null 
                && component.getId().equals(id)) {
                found[0] = component;
                return VisitResult.COMPLETE;
            }
            return VisitResult.ACCEPT;              
        }
    });

    return found[0];

}

此代码将在您传递的id中仅找到树中的第一个组件.如果树中有2个具有相同名称的组件，则必须做一些自定义操作(如果它们在2个不同的命名容器中，则可能会发生这种情况).

This code will find only the first component in the tree with the id you pass. You will have to do something custom if there are 2 components with the same name in the tree (this is possible if they are under 2 different naming containers).

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