验证< ui:repeat>< h:inputText>中的列表是否具有至少一个非空/空值 [英] Validate if list in <ui:repeat><h:inputText> has at least one non-empty/null value

问题描述

我的模型中有一个List<String>:

private List<String> list;

// Add to list: "d","e","f","a","u","l","t"
// Getter.

我在以下视图中显示它:

I'm presenting it in the view as below:

<ui:repeat value="#{bean.list}" varStatus="loop">
    <h:inputText value="#{bean.list[loop.index]}"/>
</ui:repeat>

这很好.现在，我想验证列表是否包含至少一个非空/空项目.如何为此创建自定义验证器?

This works fine. Now I'd like to validate if the list contains at least one non-empty/null item. How can I create a custom validator for this?

推荐答案

使用自定义验证程序很难做到这一点.也就是说，实际上只有一个输入组件，其状态会在每一轮迭代中发生变化.最好的选择是挂接<ui:repeat>的postValidate事件，然后通过

This isn't easily possible with a custom validator. There's namely physically only one input component whose state changes with every iteration round. Your best bet is to hook on postValidate event of <ui:repeat> and then visit its children via UIComponent#visitTree() on the UIRepeat.

这是一个开球示例:

<ui:repeat value="#{bean.list}" varStatus="loop">
    <f:event type="postValidate" listener="#{bean.validateOneOrMore}" />
    <h:inputText value="#{bean.list[loop.index]}"/>
</ui:repeat>

使用这种validateOneOrMore()方法(同样，只是一个启动示例，该方法天真地假设转发器中只有一个UIInput组件):

With this validateOneOrMore() method (again, just a kickoff example, this approach naively assumes that there's only one UIInput component in the repeater):

public void validateOneOrMore(ComponentSystemEvent event) {
    final FacesContext context = FacesContext.getCurrentInstance();
    final List<String> values = new ArrayList<>();

    event.getComponent().visitTree(VisitContext.createVisitContext(context), new VisitCallback() {
        @Override
        public VisitResult visit(VisitContext context, UIComponent target) {
            if (target instanceof UIInput) {
                values.add((String) ((UIInput) target).getValue());
            }
            return VisitResult.ACCEPT;
        }
    });

    values.removeAll(Arrays.asList(null, ""));

    if (values.isEmpty()) {
        event.getComponent().visitTree(VisitContext.createVisitContext(context), new VisitCallback() {
            @Override
            public VisitResult visit(VisitContext context, UIComponent target) {
                if (target instanceof UIInput) {
                    ((UIInput) target).setValid(false);
                }
                return VisitResult.ACCEPT;
            }
        });

        context.validationFailed();
        context.addMessage(null, new FacesMessage("Please fill out at least one!"));
    }
}

请注意，它两次访问了树；第一次收集值，第二次将这些输入标记为无效.

Note that it visits the tree twice; first time to collect the values and second time to mark those inputs invalid.

OmniFaces具有 <o:validateOneOrMore> 组件，它在固定组件上做类似的事情，但是它不是为在动态重复的组件中使用而设计的.

OmniFaces has an <o:validateOneOrMore> component which does a similar thing on fixed components, but it isn't designed for usage in dynamically repeated components.

• 验证ui:repeat中项目的顺序
• OmniFaces o:validateAllOrNone in ui:repeat或h:dataTable

• Validate order of items inside ui:repeat
• OmniFaces o:validateAllOrNone in ui:repeat or h:dataTable

这篇关于验证< ui:repeat>< h:inputText>中的列表是否具有至少一个非空/空值的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！