使用查询字符串获取重写的URL [英] Get rewritten URL with query string

问题描述

我正在使用JSF中的曲棍球URL重写.

I'm using tuckey URL rewriting with JSF.

我想获得包括用户看到的参数在内的相对URL: 例如

I would like to get the relative URL including parameters that the user sees: e.g.

example.com/mypage?param=test

如果我这样做的话

#{view.viewId}

我知道

mypage.xhtml

mypage.xhtml

我想得到的是:

mypage?param = test

mypage?param=test

推荐答案

HttpServletRequest#getRequestURI() 获取当前请求URI和 HttpServletRequest#getQueryString() 获取当前请求查询字符串.

The UIViewRoot#getViewId() returns the JSF view ID. You need to use HttpServletRequest#getRequestURI() to obtain the current request URI and HttpServletRequest#getQueryString() to obtain the current request query string.

#{request.requestURI}#{empty request.queryString ? '' : '?'}#{request.queryString}

或者，如果是转发的请求，则将其作为以 RequestDispatcher.FORWARD_REQUEST_URI 和 RequestDispatcher.FORWARD_QUERY_STRING :

Or, if it's a forwarded request, get it as a request attribute keyed with RequestDispatcher.FORWARD_REQUEST_URI and RequestDispatcher.FORWARD_QUERY_STRING respectively:

#{requestScope['javax.servlet.forward.request_uri']}#{empty requestScope['javax.servlet.forward.query_string'] ? '' : '?'}#{requestScope['javax.servlet.forward.query_string']}

笨拙的是.考虑隐藏在主模板或工具标签/功能的<c:set>中.

Clumsy yes. Consider hiding away in <c:set> of a master template, or an utility tag/function.

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