如何注册一个BroadcastReceiver（）一个线程内 [英] How to register a BroadcastReceiver() inside a thread

问题描述

我有一个soundrecorder Android的线程，我需要知道，如果麦克风/耳机连接或不同时录制，所以我需要使用一个BroadcastReceiver（）的thread.how里面我可以注册？ this.registerReceiver（）不会工作，因为它仅适用于内活动。

如果使用一个线程内broadcasereceivers是不是一个好主意，所以什么解决办法吗？

这里是code这将一个活动，不会工作线程内内工作：

  headsetReceiver =新的广播接收器（）{
        @覆盖
            公共无效的onReceive（上下文的背景下，意图意图）{
            字符串行动= intent.getAction（）;
            Log.i（广播接收器，动作）;
            如果（（action.compareTo（Intent.ACTION_HEADSET_PLUG））== 0）//如果
                                                                        //将
                                                                        //动作
                                                                        // 匹配
                                                                        // 一个
                                                                        //耳机
                                                                        // 1
            {
                INT headSetState = intent.getIntExtra（国家，0）; //获取
                                                                    //将
                                                                    //耳机
                                                                    //状态
                                                                    //财产
                INT hasMicrophone = intent.getIntExtra（话筒，0）; //获取
                                                                        //将
                                                                        //耳机
                                                                        //麦克风
                                                                        //财产
                如果（（headSetState == 0）及及（hasMicrophone == 0））//耳机
                                                                    //是
                                                                    //不插电
                                                                    //＆安培;
                                                                    // 具有
                                                                    //没有
                                                                    //麦克风
                {
                    //做什么
                }
            }
        }
    };    this.registerReceiver（headsetReceiver，新的IntentFilter（
            Intent.ACTION_HEADSET_PLUG））;
 

解决方案

您将需要上下文传递给线程构造函数，然后使用它来注册的广播接收器：

  // this.ctx传递给Thread构造
this.ctx.registerReceiver（headsetReceiver，新的IntentFilter（
            Intent.ACTION_HEADSET_PLUG））;
 

不要忘了最终{}注销您的接收器在你的线程或泄漏，可能会发生：

 终于{
       ctx.unregisterReceiver（headsetReceiver）;
}
 

为了改变主线程（如一个活动）内的UI，你需要安装一个处理程序

I have a soundrecorder android thread and i need to know if mic/headset is connected or not while recording,so i need to use a BroadcastReceiver() inside the thread.how can i register that? this.registerReceiver() wont work because it only works inside activities.

If using broadcasereceivers inside a thread is not a good idea,so whats the solution?

here is the code which would work inside an activity and wont work inside a thread:

    headsetReceiver = new BroadcastReceiver() {
        @Override
            public void onReceive(Context context, Intent intent) {
            String action = intent.getAction();
            Log.i("Broadcast Receiver", action);
            if ((action.compareTo(Intent.ACTION_HEADSET_PLUG)) == 0) // if
                                                                        // the
                                                                        // action
                                                                        // match
                                                                        // a
                                                                        // headset
                                                                        // one
            {
                int headSetState = intent.getIntExtra("state", 0); // get
                                                                    // the
                                                                    // headset
                                                                    // state
                                                                    // property
                int hasMicrophone = intent.getIntExtra("microphone", 0);// get
                                                                        // the
                                                                        // headset
                                                                        // microphone
                                                                        // property
                if ((headSetState == 0) && (hasMicrophone == 0)) // headset
                                                                    // was
                                                                    // unplugged
                                                                    // &
                                                                    // has
                                                                    // no
                                                                    // microphone
                {
                    // do whatever
                }
            }
        }
    };

    this.registerReceiver(headsetReceiver, new IntentFilter(
            Intent.ACTION_HEADSET_PLUG));

解决方案

You will need to pass the context to the Thread constructor and then use it to register the broadcast receiver:

//this.ctx is passed to the Thread constructor
this.ctx.registerReceiver(headsetReceiver, new IntentFilter(
            Intent.ACTION_HEADSET_PLUG));

Do not forget to unregister your receiver in finally{} in your Thread or leaks may occur:

finally{
       ctx.unregisterReceiver(headsetReceiver);
}

In order to change UI inside main thread(eg an activity), you will need to setup a handler

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