将具有可变属性的JSON对象解析为强类型对象 [英] Parsing JSON Object with variable properties into strongly typed object

问题描述

{
"Profile": {
    "dProperty1": {
        "a": "value",
        "b": "value",
        "c": "value",
        "d": "value",
        "e": "value"
    },
    "dProperty2": {
        "a": "value",
        "b": "value",
        "d": "value",
        "e": "value"
    },
    "dProperty3": {
        "a": "value",
        "b": "value",
        "d": "value",
        "e": "value"
       }
    }
}

我有一个JSON对象，它可以具有任意数量的动态属性.所有属性都是主要由相同字段组成的对象.如何在C#中将此JSON解析为强类型对象?

I have a JSON object, which can have any number of dynamic properties. All the properties are objects that consist of mostly of the same fields. How can i parse this JSON into a strongly typed object in C#?

推荐答案

如果必须使用强类型化的结果，我会反序列化Profile作为属性叠加的字典

If you must have strongly typed result I would deserialize Profile as a dictionary of superposition of properties

class AbscdeClass
{
    public string A { get; set; }
    public string B { get; set; }
    public string C { get; set; }
    public string D { get; set; }
    public string E { get; set; }
}

class JsonBody
{
    public Dictionary<string, AbscdeClass> Profile { get; set; }
}

并将原始JSON文本解析为

and parse original JSON text as

JsonBody json = JsonConvert.DeserializeObject<JsonBody>(jsonString);

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