使用PHP的无效JSON解析 [英] Invalid JSON parsing using PHP

问题描述

我要提取的JSON提要是无效的JSON.它完全缺少引号.我已经尝试了一些方法，例如explode()和str_replace()，以使该字符串看起来更像有效的JSON，但其中包含关联的JSON字符串，通常会使它搞砸.

I'm pulling a JSON feed that is invalid JSON. It's missing quotes entirely. I've tried a few things, like explode() and str_replace(), to get the string looking a little bit more like valid JSON, but with an associate JSON string inside, it generally gets screwed up.

这是一个例子:

id:43015,name:'John Doe',level:15,systems:[{t:6,glr:1242,n:'server',s:185,c:9}],classs:0,subclass:5

有没有适用于php的JSON解析器，可以像这样处理无效的JSON?

Are there any JSON parsers for php out there that can handle invalid JSON like this?

我正在尝试在此字符串上使用json_decode().它什么也不返回.

I'm trying to use json_decode() on this string. It returns nothing.

推荐答案

1. 所有引号应为双引号"，而不是单引号'.
2. 所有键都应加引号.
3. 整个元素应该是一个对象.

1. All the quotes should be double quotes " and not single quotes '.
2. All the keys should be quoted.
3. The whole element should be an object.

    function my_json_decode($s) {
        $s = str_replace(
            array('"',  "'"),
            array('\"', '"'),
            $s
        );
        $s = preg_replace('/(\w+):/i', '"\1":', $s);
        return json_decode(sprintf('{%s}', $s));
    }

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