在C#中覆盖Json属性名称 [英] Overwrite Json property name in c#
问题描述
我有一个包含以下字段的课程.这些属性用于在需要调用外部rest API方法时序列化为json对象.
I have a class with following fields. Those properties are used to serialize as json object when it needs to call a external rest API method.
public class Customer
{
[JsonProperty(PropertyName = "email")]
public string Email { get; set; }
[JsonProperty(PropertyName = "prop[listId]")]
public string Test{ get; set; }
// there are lot of properties
}
在属性名称Test
中,外部API服务调用需要执行以下操作,例如遵循json归档名称格式.
In the property name Test
,external API service call required some thing like following json filed name format.
prop[7]
在我的情况下,可以根据诸如test,dev和prod之类的环境来更改7
.因此,我正在寻找一种将listId值移动到app.config中的方法.
In my case this 7
can be changed according the environment like test,dev and prod.So what I'm looking for a way to move that listId value into app.config .
我已尝试按照以下步骤进行操作,但不允许这样做.对于listIdValue
,如果为其分配常数值,它将起作用.
I have tried to do it as follow but it is not allowed to do that.for the listIdValue
if assign the constant value it will work.
private string listIdValue = ConfigurationManager.AppSettings["ListIdValue"];
[JsonProperty(PropertyName = "prop["+listIdValue +"]")]
public string Test{ get; set; }
推荐答案
您将必须覆盖DefaultContractResolver
并实现您自己的机制来提供PropertyName
(以JSON).我将提供完整的示例代码,以显示运行时生成的PropertyName
的反序列化和序列化.当前,它会将Test
字段修改为Test5
(在所有型号中).您应该实现自己的机制(使用属性,保留名称,表等).
You'll have to override DefaultContractResolver
and implement your own mechanism to provide the PropertyName
(in JSON). I will provide a full example code to show deserialization and serialization with a runtime generated PropertyName
. Currently, it modifies the Test
field to Test5
(in all models). You should implement your own mechanism (using an attribute, a reserved name, a table or whatever.
class Program
{
static void Main(string[] args)
{
var customer = new Customer() {Email = "asd@asd.com", Test = "asdasd"};
var a = Serialize(customer, false);
var b = Serialize(customer, true);
Console.WriteLine(a);
Console.WriteLine(b);
var desA = Deserialize<Customer>(a, false);
var desB = Deserialize<Customer>(b, true);
Console.WriteLine("TestA: {0}", desA.Test);
Console.WriteLine("TestB: {0}", desB.Test);
}
static string Serialize(object obj, bool newNames)
{
JsonSerializerSettings settings = new JsonSerializerSettings();
settings.Formatting = Formatting.Indented;
if (newNames)
{
settings.ContractResolver = new CustomNamesContractResolver();
}
return JsonConvert.SerializeObject(obj, settings);
}
static T Deserialize<T>(string text, bool newNames)
{
JsonSerializerSettings settings = new JsonSerializerSettings();
settings.Formatting = Formatting.Indented;
if (newNames)
{
settings.ContractResolver = new CustomNamesContractResolver();
}
return JsonConvert.DeserializeObject<T>(text, settings);
}
}
class CustomNamesContractResolver : DefaultContractResolver
{
protected override IList<JsonProperty> CreateProperties(System.Type type, MemberSerialization memberSerialization)
{
// Let the base class create all the JsonProperties
// using the short names
IList<JsonProperty> list = base.CreateProperties(type, memberSerialization);
// Now inspect each property and replace the
// short name with the real property name
foreach (JsonProperty prop in list)
{
if (prop.UnderlyingName == "Test") //change this to your implementation!
prop.PropertyName = "Test" + 5;
}
return list;
}
}
public class Customer
{
[JsonProperty(PropertyName = "email")]
public string Email { get; set; }
public string Test { get; set; }
}
输出:
{
"email": "asd@asd.com",
"Test": "asdasd"
}
{
"email": "asd@asd.com",
"Test5": "asdasd"
}
TestA: asdasd
TestB: asdasd
如您所见,
如您所见,当我们使用Serialize(..., false)
时,该字段的名称为Test
;当我们使用Serialize(..., true)
时,该字段的名称为Test5
.这也适用于反序列化.
As you see, when we use Serialize(..., false)
- the field's name is Test
and when we use Serialize(..., true)
- the field's name is Test5
, as expected. This also works for deserialization.
我已将此答案用作答案: https://stackoverflow.com/a/20639697/773879
I have used this answer as insperation for my answer: https://stackoverflow.com/a/20639697/773879
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