任何将剥离对象属性为null的PHP函数吗? [英] Any PHP function that will strip properties of an object that are null?

问题描述

我正在返回从ORM中提取的对象数组的json_encode().它包含许多具有空值的属性.删除这些为空的属性的最巧妙的方法是什么?我想我可以遍历这些属性，看看它们是否为null，然后对该属性进行unset()，但是肯定有一种更优雅的方法吗?

I am returning a json_encode() of an array of objects pulled from an ORM. It includes lots of properties with a null value. What is the neatest way to remove these properties that are null? I guess I could iterate over the properties, look if they are null and then unset() that property, but surely there must be a more elegant way?

推荐答案

尝试一下；它仅适用于简单对象，但如果它来自ORM，则应该足够简单.

Try this; it will only work on a simple object, but if it's coming from an ORM it should be simple enough.

// Strips any false-y values
$object = (object) array_filter((array) $object);

感谢 Gordon's 回答的另一个问题昨天是因为给了我这个主意.

Thanks to Gordon's answer to another question yesterday for giving me the idea.

这是

• 将对象转换为关联数组，其中对象属性是键，其值是数组值
• 使用带有默认参数的 array_filter 来删除具有错误(例如空或空)值的数组条目
• 将新数组转换回简单对象

• converting the object to an associative array, where object properties are the keys and their values are the array values
• using array_filter with default arguments to remove array entries with a false (e.g. empty, or null) values
• converting the new array back to a simple object

请注意，这将删除所有具有空值的属性，包括空字符串，错误的布尔值和0，而不仅仅是空值；您可以更改array_filter调用，如果您想保留那些并且只远程那些完全为空的变量.

Note that this will remove all properties with empty values, including empty strings, false boolean values and 0s, not just nulls; you can change the array_filter call if you want to keep those and only remote those that are exactly null.

// Strips only null values
$object = (object) array_filter((array) $object, function ($val) {
    return !is_null($val);
});

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