Mule:是否有将XML转换为JSON的简单方法 [英] Mule: Is there simple way of converting XML to JSON

问题描述

有没有简单的方法可以将XML转换为JSON，而无需先将XML绑定到Java对象?

Is there simple way of converting XML to JSON, without binding XML to a java object first?

就像这是怎么做的- http://www.utilities-online.info/xmltojson/#.UrXnCvRDt0w

Just like how this does it -- http://www.utilities-online.info/xmltojson/#.UrXnCvRDt0w

如果可能的话，我不想维护XML模式.

I don't want to maintain XML schema, if at all possible.

推荐答案

我最终所做的-

  <custom-transformer class="com.mycompany.transformer.XmlToJson" name="XmlToJson" doc:name="Java"/>

  <flow name="HTTP" doc:name="HTTP">
    <http:inbound-endpoint exchange-pattern="request-response" host="localhost" port="8081" path="test" doc:name="HTTP" contentType="application/json"/>
    <http:outbound-endpoint exchange-pattern="request-response" method="GET" address="http://server-address.com" doc:name="service-call"/>
    <object-to-string-transformer doc:name="Object to String"/>
    <transformer ref="XmlToJson" doc:name="Transformer Reference"/>
</flow>

这是XmlToJson.java-

Here is XmlToJson.java --

import org.json.XML;
import org.mule.api.transformer.TransformerException;
import org.mule.transformer.AbstractTransformer;

public class XmlToJson extends AbstractTransformer{

@Override
protected Object doTransform(Object src, String enc)
        throws TransformerException {
    JSONObject jsonObj = XML.toJSONObject((String) src);
            return  jsonObj.toString();
}
}

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