PHP json_encode mysql结果 [英] php json_encode mysql result

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本文介绍了PHP json_encode mysql结果的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个简单的mysql_query,我想在json中编码results(title= > $title, price => $price etc).

I have a simple mysql_query and I would like to encode the results(title= > $title, price => $price etc) in json .


$sql = mysql_query("SELECT * FROM item_details WHERE posting_id='$item_number'");

 while($row = mysql_fetch_array($sql))
{
   $title = base64_decode($row['title']);
   $price = $row['price'];
   $seller_user = $row['user'];
}

推荐答案

$sql = mysql_query("SELECT * FROM item_details WHERE posting_id='$item_number'");
$results = array();
while($row = mysql_fetch_array($sql))
{
   $results[] = array(
      'title' => base64_decode($row['title']),
      'price' => $row['price'],
      'seller_user' => $row['user']
   );
}
$json = json_encode($results);

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