Python中的自定义JSON sort_keys顺序 [英] custom JSON sort_keys order in Python
问题描述
Python 2.6中是否可以为JSON的sort_keys提供自定义键或cmp函数?
Is there any way in Python 2.6 to supply a custom key or cmp function to JSON's sort_keys?
我有一个来自JSON的字典列表,如下所示:
I've got a list of dicts coming from JSON like so:
[
{
"key": "numberpuzzles1",
"url": "number-puzzle-i.html",
"title": "Number Puzzle I",
"category": "nestedloops",
"points": "60",
"n": "087"
},
{
"key": "gettingindividualdigits",
"url": "getting-individual-digits.html",
"title": "Getting Individual Digits",
"category": "nestedloops",
"points": "80",
"n": "088"
}
]
...我已将其存储到列表变量assigndb
中.我希望能够加载JSON,对其进行修改,然后使用dumps
(或其他任何方式)将其序列化回去,并保持键的顺序不变.
...which I've stored into the list variable assigndb
. I'd like to be able to load in the JSON, modify it, and serialized it back out with dumps
(or whatever), keeping the orders of the keys intact.
到目前为止,我已经尝试过这样的事情:
So far, I've tried something like this:
ordering = {'key': 0, 'url': 1, 'title': 2, 'category': 3,
'flags': 4, 'points': 5, 'n': 6}
def key_func(k):
return ordering[k]
# renumber assignments sequentially
for (i, a) in enumerate(assigndb):
a["n"] = "%03d" % (i+1)
s = json.dumps(assigndb, indent=2, sort_keys=True, key=key_func)
...但是,当然dumps
不像list.sort()
那样支持自定义键.带有自定义JSONEncoder
的内容?我似乎无法解决问题.
...but of course dumps
doesn't support a custom key like list.sort()
does. Something with a custom JSONEncoder
maybe? I can't seem to get it going.
推荐答案
这有点难看,但是如果tokland的解决方案对您不起作用:
This is kind of ugly, but in case tokland's solution does not work for you:
data = [{'category': 'nestedloops', 'title': 'Number Puzzle I', 'url': 'number-puzzle-i.html', 'n': '087', 'points': '60', 'key': 'numberpuzzles1'}, {'category': 'nestedloops', 'title': 'Getting Individual Digits', 'url': 'getting-individual-digits.html', 'n': '088', 'points': '80', 'key': 'gettingindividualdigits'}]
ordering = {'key': 0, 'url': 1, 'title': 2, 'category': 3,
'flags': 4, 'points': 5, 'n': 6}
outlist = []
for d in data:
outlist.append([])
for k in sorted(d.keys(), key=lambda k: ordering[k]):
outlist[-1].append(json.dumps({k: d[k]}))
for i, l in enumerate(outlist):
outlist[i] = "{" + ",".join((s[1:-1] for s in outlist[i])) + "}"
s = "[" + ",".join(outlist) + "]"
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