将异常转换为JSON [英] Convert Exception to JSON

问题描述

在Java 7中是否可以将Exception对象转换为Json?

Is it possible, in Java 7, to convert an Exception object into Json?

示例:

try {      
    //something
} catch(Exception ex) {     
    Gson gson = new Gson();
    System.out.println(gson.toJson(ex));
}

推荐答案

理论上，您还可以遍历堆栈跟踪中的元素并生成类似于以下内容的东西:

In theory, you could also iterate over the elements in a stack trace and generate something that looks like:

{ "NullPointerException" :
    { "Exception in thread \"main\" java.lang.NullPointerException",
        { 
          "Book.java:16" : "com.example.myproject.Book.getTitle",
          "Author.java:25" : "at com.example.myproject.Author.getBookTitles",
          "Bootstrap.java:14" : "at com.example.myproject.Bootstrap.main()"
        }
    },
  "Caused By" :
    { "Exception in thread \"main\" java.lang.NullPointerException",
        { 
          "Book.java:16" : "com.example.myproject.Book.getTitle",
          "Author.java:25" : "at com.example.myproject.Author.getBookTitles",
          "Bootstrap.java:14" : "at com.example.myproject.Bootstrap.main()"
        }
    }
}

您可以像这样重复访问:

You can iterate the exception like this:

catch (Exception cause) {
    StackTraceElement elements[] = cause.getStackTrace();
    for (int i = 0, n = elements.length; i < n; i++) {       
        System.err.println(elements[i].getFileName()
            + ":" + elements[i].getLineNumber() 
            + ">> "
            + elements[i].getMethodName() + "()");
    }
}

这篇关于将异常转换为JSON的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！