Kendo数据网格-如何从嵌套的JSON对象设置列值? [英] Kendo data grid - how to set column value from nested JSON object?
本文介绍了Kendo数据网格-如何从嵌套的JSON对象设置列值?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有JSON,其结构如下:
I have JSON with structure like this:
"id":1,
"user_role":"ADMIN",
"state":"ACTIVE",
"address":{
"street":"test 59",
"city":"City test",
"post_number":"25050"
},
如何使用字段和模型中的设置将address.street的值传递到列中?
How I should to pass values of address.street into column using setting in fields and model?
非常感谢您的任何建议.
Many thanks for any advice.
推荐答案
如果要在单个列中显示所有值,请执行@RobinGiltner建议的操作.
If you want to show all values in a single column do what @RobinGiltner suggests.
如果要在不同的列中显示address
的每个成员,可以执行以下操作:
If you want to show each member of address
in a different column you can do:
var grid = $("#grid").kendoGrid({
dataSource: data,
editable: true,
columns : [
{ field: "id", title: "#" },
{ field: "user_role", title: "Role" },
{ field: "address.street", title: "Street" },
{ field: "address.city", title: "City" },
{ field: "address.post_number", title: "Post#" }
]
}).data("kendoGrid");
即:使用address.street
作为字段名称.这样甚至可以像示例中一样编辑字段: http://jsfiddle.net/OnaBai/L6LwW/
i.e.: use address.street
as name of the field. This would allow you even to edit the field as in the example: http://jsfiddle.net/OnaBai/L6LwW/
这篇关于Kendo数据网格-如何从嵌套的JSON对象设置列值?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文