如何从数组中选择JSON项目 [英] How to select json item from the array
本文介绍了如何从数组中选择JSON项目的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
如何从下面的JSON中,如何使用for循环和ajax来检索笔记和笔记中的标题?
From the below JSON, how can I retrieve title from the note and notes using a for loop and ajax to retrieve?
{
"infos": {
"info": [
{
"startYear": "1900",
"endYear": "1930",
"timeZoneDesc": "daweerrewereopreproewropewredfkfdufssfsfsfsfrerewrBlahhhhh..",
"timeZoneID": "1",
"note": {
"notes": [
{
"id": "1",
"title": "Mmm"
},
{
"id": "2",
"title": "Wmm"
},
{
"id": "3",
"title": "Smm"
}
]
},
"links": [
{ "id": "1", "title": "Red House", "url": "http://infopedia.nl.sg/articles/SIP_611_2004-12-24.html" },
{ "id": "2", "title": "Joo Chiat", "url": "http://www.the-inncrowd.com/joochiat.htm" },
{ "id": "3", "title": "Bake", "url": "https://thelongnwindingroad.wordpress.com/tag/red-house-bakery" }
]
}
我尝试了下面的代码,但是它不起作用-它要么说:
I tried out the code below but it doesn't work - it either says:
为空
不是对象
length为空
r不是对象
var detail = eval(xmlhttprequest.responseText)
var rss = detail.infos.info
for(var i = 0; i<rss.length; i++)
startyear += rss[i].startyear
推荐答案
使用
for (i = 0; i < 3; i++) {
alert(JSON.infos.info[0].note.notes[i].title);
}
在这里尝试: JSFIDDLE工作示例
顺便说一句,您的JSON无效.使用此JSON:
BTW your JSON is not valid. Use this JSON:
var JSON = {
"infos": {
"info": [
{
"startYear": "1900",
"endYear": "1930",
"timeZoneDesc": "daweerrewereopreproewropewredfkfdufssfsfsfsfrerewrBlahhhhh..",
"timeZoneID": "1",
"note": {
"notes": [
{
"id": "1",
"title": "Mmm"
},
{
"id": "2",
"title": "Wmm"
},
{
"id": "3",
"title": "Smm"
}
]
},
"links": [
{
"id": "1",
"title": "Red House",
"url": "http://infopedia.nl.sg/articles/SIP_611_2004-12-24.html"
},
{
"id": "2",
"title": "Joo Chiat",
"url": "http://www.the-inncrowd.com/joochiat.htm"
},
{
"id": "3",
"title": "Bake",
"url": "https://thelongnwindingroad.wordpress.com/tag/red-house-bakery"
}
]
}
]
}
}
这是您想要的:
Here is what you want:
var infoLength= JSON.infos.info.length;
for (infoIndex = 0; infoIndex < infoLength; infoIndex++) {
var notesLength= JSON.infos.info[infoIndex].note.notes.length;
for (noteIndex = 0; noteIndex < notesLength; noteIndex++) {
alert(JSON.infos.info[infoIndex].note.notes[noteIndex].title);
}
}
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