区分大小写的JSON Unmarshal结构 [英] JSON Unmarshal struct case-sensitively

问题描述

有没有办法使json.Unmarshal 不接受不区分大小写的匹配?我收到带有标签的JSON，例如"e"和"E"，并想解组带有标签"e"的对象，但忽略带有"E"的对象.现在，我发现的唯一解决方案是定义一个包含两个标签的结构，然后简单地忽略标签"E"，但是我正在寻找一种更清洁的解决方案.

Is there any way to make json.Unmarshal not accept a case-insensitive match? I receive a JSON with tags such as "e" and "E" and would like to unmarshal the object with tag "e" but ignore the one with "E". Right now the only solution I found was to define a struct containing both tags and then to simply ignore tag "E", but I'm looking for a cleaner solution.

摘自官方文档:

要将JSON解组到结构中，Unmarshal会将传入的对象键与Marshal使用的键(结构字段名称或其标记)进行匹配，希望使用精确匹配，但还要接受不区分大小写的匹配.

To unmarshal JSON into a struct, Unmarshal matches incoming object keys to the keys used by Marshal (either the struct field name or its tag), preferring an exact match but also accepting a case-insensitive match.

推荐答案

不幸的是，标准json库当前不支持此功能.

Unfortunately this is not something currently supported by the standard json library.

根据 https://golang.org/pkg/encoding/json/#Unmarshal

Unmarshal将传入的对象键与Marshal使用的键(结构字段名称或其标记)进行匹配，更喜欢精确匹配，但也接受不区分大小写的匹配

Unmarshal matches incoming object keys to the keys used by Marshal (either the struct field name or its tag), preferring an exact match but also accepting a case-insensitive match

无法关闭此行为.

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