属性名称为*时,如何解析PHP对象? [英] How do I parse a PHP object when the attribute name is *?

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问题描述

可能重复:
对象属性名称中的特殊字符

Possible Duplicate:
Special characters in property name of object

我正在从MediaWiki的API解析JSON响应:

I'm parsing a JSON response from MediaWiki's API: Requested URL

我通过json_decode()运行它,然后拉一些它.我的问题是内容的属性名称是*.当我尝试访问内容时(如下面的vardumped json_decoded示例末尾的140,950字符串),我收到PHP错误,如下所示:

I run it through json_decode() and then pull some pieces of it. The problem I have is that the attribute name for the content is *. I get a PHP error when I try to access the content ( the 140,950 character string at the end of my vardumped json_decoded example below ) like this:

foreach( $Response->query->pages as $page_id => $Page ) {
    $this->id                   = $Page->pageid;
    $this->title                = $Page->title;
    $this->content_with_markup  = $Page->revisions[0]->*;
}

PHP错误:PHP Parse error: syntax error, unexpected '*'

pageidtitle正常工作.

这是给我一些问题的JSON_Decoded对象:

Here is the piece of JSON_Decoded object that is giving me problems:

object(stdClass)#5 (1) {
  ["11968"]=>
  object(stdClass)#6 (4) {
    ["pageid"]=>
    int(11968)
    ["ns"]=>
    int(0)
    ["title"]=>
    string(17) "George Washington"
    ["revisions"]=>
    array(1) {
      [0]=>
      object(stdClass)#7 (2) {
        ["contentformat"]=>
        string(11) "text/x-wiki"
        ["*"]=>
        string(140950) "{{About|the first President of the United States|other uses}}...

如何访问名为*的属性中包含的内容?

推荐答案

一如既往.

...->{'*'}->...

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