JSON数据到Web服务-如何定义期望的JSON数据 [英] JSON data to web service- how do define expected JSON data

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问题描述

我正在用PHP构建一个RESTful Web服务,该服务接受JSON作为其有效负载 . 现在,我的问题是,如何准确地向用户描述JSON请求的格式?我是JSON的新手,但我认为我100%都不了解.

I am building a RESTful web service in PHP that accepts JSON as its payload . Now, my question is, how exactly do I describe to the user the format that the JSON request comes in? I am new to JSON and don't think I have a grasp 100%.

其他用户系统是否会基本上用我需要的键值对创建一个数据结构(如数组),将其编码为JSON并将其发送到我的Web服务?

Will the other users system basically create a data structure (such an array) with the key value pairs that I need, encode this in JSON and send it to my web service?

我真的会给他们一个数组需要看起来像什么的副本吗? 谢谢!

Do I literally give them a copy of what the array needs to look like? Thanks!

推荐答案

遵循REST的准则,您从API用户那里获得的输入应该是URL的一部分(对于GET请求;不是更新数据,即http://example.com/api/doc/1243),或者应该是POST变量(在HTTP请求的正文中发送到同一URL).

Adhering to the guidelines of REST, the input you get from the users of the API should either be part of the URL (for a GET request; doesn't update data, i.e. http://example.com/api/doc/1243), or should be a POST variable (sent in the body of the HTTP request, to the same URL).

因此,对于文档来说,您需要做的只是指出端点URL(http://example.com/api/doc/1243),他们需要使用POST的事实以及变量的含义(即titlebodyauthor , 等等.).然后,用户将根据需要创建适当的HTTP请求,并且在服务器端,因为您使用的是PHP,所以将从$_POST数组(即$_POST['title']$_POST['body']等)中拉出他们的变量.

So for documentation, all you should need to do is indicate the endpoint URL (http://example.com/api/doc/1243), the fact they need to use POST, and what the variables are (i.e. title, body, author, etc.). Then users will form the proper HTTP request however they want, and on your server end, because you're using PHP, you'll pull their variables from the $_POST array (i.e. $_POST['title'], $_POST['body'], etc.)

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