如何使用php获取json值 [英] how to get json value with php

问题描述

此处的API参数响应:

Here parameters of API respond :

{"cod":"200","message":0.0045,
"city":{"id":1851632,"name":"Shuzenji",
"coord":{"lon":138.933334,"lat":34.966671},
"country":"JP"},
"cnt":38,
"list":[{
        "dt":1406106000,
        "main":{
            "temp":298.77,
            "temp_min":298.77,
            "temp_max":298.774,
            "pressure":1005.93,
            "sea_level":1018.18,
            "grnd_level":1005.93,
            "humidity":87},
        "weather":[{"id":804,"main":"Clouds","description":"overcast clouds","icon":"04d"}],
        "clouds":{"all":88},
        "wind":{"speed":5.71,"deg":229.501},
        "sys":{"pod":"d"},
        "dt_txt":"2014-07-23 09:00:00"}
        ]}

我的php代码无法获得覆盖"的值:

I can't get value "Overcast" with my php code :

   echo $data['list'][0]['weather']['description'];
   echo $data['list'][1]['weather']['description'];

...

我尝试了几种组合，我读了这篇文章 如何使用PHP从JSON提取数据?

I tried several combinaison, i read this article How do I extract data from JSON with PHP?

但是没有任何作用...

But nothing work...

推荐答案

看起来天气"是一个数组.

It looks like 'weather' is an array.

尝试$data['list'][0]['weather'][0]['description'];

这篇关于如何使用php获取json值的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！