Python json.loads ValueError，需要定界符 [英] Python json.loads ValueError, expecting delimiter

问题描述

我正在将Postgres表提取为json.输出文件包含以下行:

I am extracting a postgres table as json. The output file contains lines like:

{"data": {"test": 1, "hello": "I have \" !"}, "id": 4}

现在我需要使用json.loads将它们加载到我的python代码中，但出现此错误:

Now I need to load them in my python code using json.loads, but I get this error:

Traceback (most recent call last):
  File "test.py", line 33, in <module>
    print json.loads('''{"id": 4, "data": {"test": 1, "hello": "I have \" !"}}''')
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/__init__.py", line 338, in loads
    return _default_decoder.decode(s)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/decoder.py", line 365, in decode
    obj, end = self.raw_decode(s, idx=_w(s, 0).end())
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/decoder.py", line 381, in raw_decode
    obj, end = self.scan_once(s, idx)
ValueError: Expecting , delimiter: line 1 column 50 (char 49)

我发现解决方法是向\"添加另一个\.所以，如果我通过

I figured out the fix is to add another \ to \". So, if I pass

{"data": {"test": 1, "hello": "I have \\" !"}, "id": 4}

到json.loads，我得到了:

{u'data': {u'test': 1, u'hello': u'I have " !'}, u'id': 4}

是否有一种无需添加额外的\的方法?像将参数传递给json.loads之类的东西?

Is there a way to do this without adding the extra \? Like passing a parameter to json.loads or something?

推荐答案

您可以指定所谓的原始字符串":

You can specify so called "raw strings":

>>> print r'{"data": {"test": 1, "hello": "I have \" !"}, "id": 4}'
{"data": {"test": 1, "hello": "I have \" !"}, "id": 4}

他们不解释反斜杠.

通常的字符串将\"更改为"，因此您可以在字符串中使用"字符，这些字符本身受双引号限制:

Usual strings change \" to ", so you can have " characters in strings that are themselves limited by double quotes:

>>> "foo\"bar"
'foo"bar'

因此，从\"到"的转换不是由json.loads完成，而是由Python本身完成.

So the transformation from \" to " is not done by json.loads, but by Python itself.

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