Restlet用JSON接收和响应实现发布 [英] Restlet implementing post with json receive and response
问题描述
首先,我想知道的是我在做什么,这是正确的方法.
First, what i wanted to know is what i am doing is the right way to do it.
我有一个场景,我将收到一个json请求,并且我必须用它来更新数据库,一旦数据库更新,我就必须以json确认来回复.
I have a scenario where i have will receive a json request and i have to update the database with that, once the db is updated i have to respond back with the json acknowledgment.
到目前为止,我所做的就是创建如下的类扩展应用程序:
What i have done so far is create the class extending application as follows:
@Override
public Restlet createRoot() {
// Create a router Restlet that routes each call to a
// new instance of ScanRequestResource.
Router router = new Router(getContext());
// Defines only one route
router.attach("/request", RequestResource.class);
return router;
}
我的资源类正在扩展ServerResource,我的资源类中具有以下方法
My resource class is extending the ServerResource and i have the following method in my resource class
@Post("json")
public Representation post() throws ResourceException {
try {
Representation entity = getRequestEntity();
JsonRepresentation represent = new JsonRepresentation(entity);
JSONObject jsonobject = represent.toJsonObject();
JSONObject json = jsonobject.getJSONObject("request");
getResponse().setStatus(Status.SUCCESS_ACCEPTED);
StringBuffer sb = new StringBuffer();
ScanRequestAck ack = new ScanRequestAck();
ack.statusURL = "http://localhost:8080/status/2713";
Representation rep = new JsonRepresentation(ack.asJSON());
return rep;
} catch (Exception e) {
getResponse().setStatus(Status.SERVER_ERROR_INTERNAL);
}
我首先关心的是我在实体中接收到的对象是inputrepresentation,因此,当我从创建的jsonrepresentation中获取jsonobject时,我总是会得到空/空对象.
My first concern is the object i receive in the entity is inputrepresentation so when i fetch the jsonobject from the jsonrepresentation created i always get empty/null object.
我尝试通过以下代码以及附加的客户端传递json请求
I have tried passing the json request with the following code as well as the client attached
function submitjson(){
alert("Alert 1");
$.ajax({
type: "POST",
url: "http://localhost:8080/thoughtclicksWeb/request",
contentType: "application/json; charset=utf-8",
data: "{request{id:1, request-url:http://thoughtclicks.com/status}}",
dataType: "json",
success: function(msg){
//alert("testing alert");
alert(msg);
}
});
};
曾经打电话给客户的客户
Client used to call
ClientResource requestResource = new ClientResource("http://localhost:8080/thoughtclicksWeb/request");
Representation rep = new JsonRepresentation(new JSONObject(jsonstring));
rep.setMediaType(MediaType.APPLICATION_JSON);
Representation reply = requestResource.post(rep);
对此有任何帮助或线索是值得赞赏的吗?
Any help or clues on this is hight appreciated ?
谢谢, 拉胡尔
推荐答案
仅使用1个JAR jse-xyz/lib/org.restlet.jar ,您可以在客户端手动构建JSON对于简单的请求:
Using just 1 JAR jse-x.y.z/lib/org.restlet.jar, you could construct JSON by hand at the client side for simple requests:
ClientResource res = new ClientResource("http://localhost:9191/something/other");
StringRepresentation s = new StringRepresentation("" +
"{\n" +
"\t\"name\" : \"bank1\"\n" +
"}");
res.post(s).write(System.out);
在服务器端,仅使用2个JAR- gson-x.y.z.jar 和 jse-x.y.z/lib/org.restlet.jar :
At the server side, using just 2 JARs - gson-x.y.z.jar and jse-x.y.z/lib/org.restlet.jar:
public class BankResource extends ServerResource {
@Get("json")
public String listBanks() {
JsonArray banksArray = new JsonArray();
for (String s : names) {
banksArray.add(new JsonPrimitive(s));
}
JsonObject j = new JsonObject();
j.add("banks", banksArray);
return j.toString();
}
@Post
public Representation createBank(Representation r) throws IOException {
String s = r.getText();
JsonObject j = new JsonParser().parse(s).getAsJsonObject();
JsonElement name = j.get("name");
.. (more) .. ..
//Send list on creation.
return new StringRepresentation(listBanks(), MediaType.TEXT_PLAIN);
}
}
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