将数据从MySQL提取到json数组中 [英] Pulling data from MySQL into json array

问题描述

我正在尝试使用php中的json从数据库中提取数据.我需要具体说明一些要素，然后将它们发布在页面上.

I'm trying to pull data from my database using json in php. I have a few elements I need to specific then to post them on a page.

我想从mysql中获取"数据并将其返回给json_encode.如何使用SELECT方法执行此操作.有些人使用了PDO方法，另一些人使用了mysql_assoc，这使我感到困惑.

I want to "fetch" the data from mysql and return it to a json_encode. How can I do this using the SELECT method. Some had used PDO methods and other have used mysql_assoc, which confuses me.

例如，

我有以下行:'id'，'title'，'start'，'backgroundColor'...等.以及所有这些的默认值. ($ array [] ="someValue = default")

I have rows of: 'id' , 'title' , 'start', 'backgroundColor'...etc. along with a default value for all of them. ($array[] = "someValue = default")

我希望它像这样导出:

array(
      'id' => 1,
      'title' => "someTitle",
      'start' => "2012-04-16",
      'backgroundColor' => "blue",
      'someValue' = > "default",
      ...
      ),   ....
 ));

如果有人能以最好的细节帮助我，我会很棒的！

If anyone could help me with this with the best detail, I'd be awesome!

推荐答案

如果您想使用PDO进行此操作，请参见以下示例:

If you wanted to do this with PDO then here is an example:

<?php 
$dbh = new PDO("mysql:host=localhost;dbname=DBNAME", $username, $password);

$sql = "SELECT `id`, `title`, `time`, `start`, `backgroundColor` 
        FROM my_table";

$result = $dbh->query($sql)->fetchAll(PDO::FETCH_ASSOC);
//To output as-is json data result
//header('Content-type: application/json');
//echo json_encode($result);

//Or if you need to edit/manipulate the result before output
$return = [];
foreach ($result as $row) {
    $return[] = [ 
        'id' => $row['id'],
        'title' => $row['title'],
        'start' => $row['start'].' '.$row['time'],
        'backgroundColor' => $row['backgroundColor']
    ];
}
$dbh = null;

header('Content-type: application/json');
echo json_encode($return);
?>

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