将嵌套的JSON转换为CSV [英] Convert nested JSON to CSV

问题描述

我正在将具有10个以上级别的嵌套JSON对象转换为C#.NET中的CSV文件.

I am converting a nested JSON object with more than 10 levels to CSV file in C# .NET.

我一直在使用JavaScriptSerializer().Deserialize<ObjectA>(json)或XmlNode xml = (XmlDocument)JsonConvert.DeserializeXmlNode(json)分解对象.有了这些对象，我可以进一步将其写入CSV文件.但是，现在JSON对象进一步扩展了.大多数未真正使用的数据，所以我更喜欢原始数据转储.

I have been using JavaScriptSerializer().Deserialize<ObjectA>(json) or XmlNode xml = (XmlDocument)JsonConvert.DeserializeXmlNode(json) to break down the object. With the objects I can further write into CSV file. However now the JSON object further expand. Most data that is not really in use so I would prefer a raw data dump.

是否可以将数据转储为csv格式而不用声明结构呢?

Is that easier way I can just dump the data into csv format without declaring the structure?

示例JSON

{
"F1":1,
"F2":2,
"F3":[
    {
        "E1":3,
        "E2":4
    },
    {
        "E1":5,
        "E2":6
    },  
    {
        "E1":7,
        "E2":8,
        "E3":[
            {
                "D1":9,
                "D2":10
            }
        ]
    },      
]
}   

我期望的CSV输出是

F1,F2,E1,E2,D1,D2
1,2
1,2,3,4
1,2,5,6
1,2,7,8,9,10

推荐答案

您的请求中有一个不一致的地方:您希望为具有子对象的根对象生成一行，但是您不希望将其作为一行为"F3[2]"对象生成的，该对象也具有子对象.听起来您的规则是，为具有至少一个原始值属性的对象打印一行，只要该对象是根对象或不具有至少具有一个原始值属性的后代对象" .这有点棘手，但是可以使用 LINQ to JSON

There's an inconsistency in your request: you want a row to be generated for the root object, which has children, but you don't want a row to be generated for the "F3[2]" object, which also has children. So it sounds like your rule is, "print a row for an object with at least one primitive-value property, as long as that object is either the root object or does not have descendant objects with at a least one primitive-value property". That's a little tricky, but can be done with LINQ to JSON

        var obj = JObject.Parse(json);

        // Collect column titles: all property names whose values are of type JValue, distinct, in order of encountering them.
        var values = obj.DescendantsAndSelf()
            .OfType<JProperty>()
            .Where(p => p.Value is JValue)
            .GroupBy(p => p.Name)
            .ToList();

        var columns = values.Select(g => g.Key).ToArray();

        // Filter JObjects that have child objects that have values.
        var parentsWithChildren = values.SelectMany(g => g).SelectMany(v => v.AncestorsAndSelf().OfType<JObject>().Skip(1)).ToHashSet();

        // Collect all data rows: for every object, go through the column titles and get the value of that property in the closest ancestor or self that has a value of that name.
        var rows = obj
            .DescendantsAndSelf()
            .OfType<JObject>()
            .Where(o => o.PropertyValues().OfType<JValue>().Any())
            .Where(o => o == obj || !parentsWithChildren.Contains(o)) // Show a row for the root object + objects that have no children.
            .Select(o => columns.Select(c => o.AncestorsAndSelf()
                .OfType<JObject>()
                .Select(parent => parent[c])
                .Where(v => v is JValue)
                .Select(v => (string)v)
                .FirstOrDefault())
                .Reverse() // Trim trailing nulls
                .SkipWhile(s => s == null)
                .Reverse());

        // Convert to CSV
        var csvRows = new[] { columns }.Concat(rows).Select(r => string.Join(",", r));
        var csv = string.Join("\n", csvRows);

        Console.WriteLine(csv);

使用

public static class EnumerableExtensions
{
    // http://stackoverflow.com/questions/3471899/how-to-convert-linq-results-to-hashset-or-hashedset
    public static HashSet<T> ToHashSet<T>(this IEnumerable<T> source)
    {
        return new HashSet<T>(source);
    }
}

哪个输出:

F1,F2,E1,E2,D1,D2
1,2
1,2,3,4
1,2,5,6
1,2,7,8,9,10

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