如何在Java Spring中使控制器端点获取两个不同的对象? [英] How to make controller endpoint to get two different objects in java spring?

问题描述

我有一台用Java和spring构建的服务器.

I have a server built with java and spring.

我想做的是，具有相同端点的控制器将获得两个不同的对象.

What i am trying to do is that my controller with the same endpoint will get two different objects.

这是我的意思的示例:

我知道我可以做到:

  public class Option1{
   private String name;
   ...
     //getter and setter
    }

public class Option2{
 private Long id;
  ...
//getter and setter
}

@Controller
public class Controller{

 @RequestMapping(value = "service/getData/option1", method = RequestMethod.POST)
 @ResponseBody
 public String searchProv(@ResponseBody Option1 data1){
  return "option1"
   }

@RequestMapping(value = "service/getData/option2", method = RequestMethod.POST)
@ResponseBody
public String searchProv(@ResponseBody Option2 data2){
  return "option2"
  }
}

但是我想知道是否可以将不同的json对象传递到同一端点并做到这一点:

but I wonder if it is possible to passing different json object to the same endpoint and do that:

 @Controller
public class Controller{

 @RequestMapping(value = "service/getData", method = RequestMethod.POST)
 @ResponseBody
 public ResponseEntity<Any> getData(@ResponseBody Option1And2 data){
if(data instanceof Option1){
  return return ResponseEntity<Any>(data.name,HttpStatus.OK)
}        
if(data instanceof Option2){
   return ResponseEntity<Any>(data.id,HttpStatus.OK)
}
 return ResponseEntity<Any>("ok",HttpStatus.OK)
  }

使得"Option1And2"是通用对象可以是option1或option2.

such that 'Option1And2' is generic object can be option1 or option2.

我试图将'Option1And2'替换为'Any'，但操作不顺利，因为我得到了键和值的列表

I tried to replace 'Option1And2' to 'Any' but it didn't went well because I get a list of keys and values

推荐答案

您应使用 JsonNode 对象.

对于您的示例，您应该执行以下操作:

for your example you should do this:

 @Controller
 public class Controller{

 @RequestMapping(value = "service/getData", method = RequestMethod.POST)
 @ResponseBody
 public ResponseEntity<Any> getData(@RequestBody JsonNode jsonNode){

   ObjectMapper obj = new ObjectMapper();

  if(jsonNode.has("name"){
   Option1 result= obj.convertValue(jsonNode,Option1.class)
  return ResponseEntity<Any>(result.name,HttpStatus.OK)
    }    

   else {

   Option2 result= obj.convertValue(jsonNode,Option2.class)
   return ResponseEntity<Any>(result.id,HttpStatus.OK)
    }

    return ResponseEntity<Any>("ok",HttpStatus.OK)
     }

您应该从此处导入的JsonNode和ObjectMapper:

the JsonNode and the ObjectMapper you should import from here:

import com.fasterxml.jackson.databind.ObjectMapper
import com.fasterxml.jackson.databind.JsonNode;

此链接应该可以帮助您更好地了解JsonNode并为您提供更多详细信息.

this link should help you to understand better on JsonNode and give you more details.

和此链接应该可以帮助您实现从JsonNode到Java对象(PO​​JO)的convertValue.

and this link should help you with the convertValue from JsonNode to java object(POJO).

这篇关于如何在Java Spring中使控制器端点获取两个不同的对象?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！