@ResourceMapping接受来自Ajax请求的JSON [英] @ResourceMapping that accepts JSON from Ajax request

问题描述

我正在搜索如何在Spring Portlet MVC的@ResourceMapping中解释JSON参数.当我添加@RequestBody时，收到消息:不支持@RequestBody.

I'm searching how I can interprete a JSON parameter in my @ResourceMapping in Spring Portlet MVC. When I add @RequestBody, I got the message: @RequestBody is not supported... Really stuck on this one.

我有这个:

查看侧:

<portlet:resourceURL var="getTest" id="ajaxTest" ></portlet:resourceURL>

    <p>
        <button onClick="executeAjaxTest();">Klik mij!</button>
        <button onClick="$('#ajaxResponse').html('');">Klik mij!</button>
    </p>
    <p>
        <h3>Hieronder het antwoord:</h3>
        <h4 id="ajaxResponse"></h4>
    </p>

    <script>
        function executeAjaxTest() {

            var jsonObj = {
                    user: "Korneel",
                    password: "testpassword",
                    type: {
                        testParam: "test",
                    }
                }

            console.debug(JSON.stringify(jsonObj));
            $.ajax({
                dataType: "json",
                contentType:"application/json",
                mimeType: 'application/json',
                url:"<%=getTest%>",
                data:JSON.stringify(jsonObj),
                success : function(data) {
                    $("#ajaxResponse").html(data['testString']);
                }
            });

        }
    </script>

控制器端:

@ResourceMapping(value="ajaxTest")
    @ResponseBody
    public void ajaxTestMethod(ResourceRequest request, ResourceResponse response) throws IOException, ParseException {

        LOGGER.debug("ajax method");

        JSONObject json = JSONFactoryUtil.createJSONObject();
        json.put("testString", "Ik ben succesvol verstuurd geweest!");
        response.getWriter().write(json.toString());
}

如何使用spring magic将JSON数据自动映射到我自己的模型? 注意:它是Spring Portlet MVC，而不是常规的Spring MVC.

How can I use the spring magic to auto map this JSON data to my own model? Note: It's Spring Portlet MVC, not regular Spring MVC..

推荐答案

您需要像这样构建json对象:

You need to build your json object like this:

var jsonObj = {
                user: "Korneel",
                password: "testpassword",
                "type.testParam" : "test"
            };

$.ajax({
            dataType: "json",
            contentType:"application/json",
            mimeType: 'application/json',
            url:"<%=getTest%>",
            data:jsonObj,
            success : function(data) {
                $("#ajaxResponse").html(data['testString']);
            }
        });

在您的控制器中，您应该使用@ModelAttribute批注:

In your Controller you should use the @ModelAttribute annotation:

@ModelAttribute(value = "jsonObj")
public JsonObjCommand obtenerJsonObjCommand() {
    JsonObjCommand jsonObjCommand = new JsonObjCommand();
    return jsonObjCommand;
}

@ResourceMapping(value = "ajaxTest")
public void ajaxTestMethod(
        ResourceRequest request,
        ResourceResponse response,
        @ModelAttribute(value = "jsonObj") JsonObjCommand jsonObjCommand)
        throws IOException, ParseException {
    LOGGER.debug("USER: " + jsonObjCommand.getUser());
    LOGGER.debug("Password: " + jsonObjCommand.getPassword());
    LOGGER.debug("TestParam: " + jsonObjCommand.getType().getTestParam());
    LOGGER.debug("ajax method");

    JSONObject json = JSONFactoryUtil.createJSONObject();
    json.put("testString", "Ik ben succesvol verstuurd geweest!");
    response.getWriter().write(json.toString());
}

别忘了你的豆子:

public class JsonObjCommand {

private String user;
private String password;
private TypeJson type;

public String getUser() {
    return user;
}
public void setUser(String user) {
    this.user = user;
}
public String getPassword() {
    return password;
}
public void setPassword(String password) {
    this.password = password;
}
public TypeJson getType() {
    return type;
}
public void setType(TypeJson type) {
    this.type = type;
}

}

public class TypeJson {

private String testParam;

public String getTestParam() {
    return testParam;
}

public void setTestParam(String testParam) {
    this.testParam = testParam;
}

}

这篇关于@ResourceMapping接受来自Ajax请求的JSON的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！