Scala Play Json阅读 [英] Scala Play Json Reads

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本文介绍了Scala Play Json阅读的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有以下示例代码.

import play.api.libs.json._
import play.api.libs.functional.syntax._
import play.api.data.validation.ValidationError
import play.api.libs.json.Reads._

case class Retailer(firstName:String,lastName:String,email:String,mobileNo:String,password:String)
case class Business(name:String,preferredUrl:String,businessPhone:String,retailer:Retailer)

object JsonTest {
  val jsonValue = """
  {
    "business":
    {
      "name":"Some Business Name",
      "preferredUrl":"someurl",
      "businessPhone":"somenumber",
      "retailer":
      {
        "firstName":"Some",
        "lastName":"One",
        "email":"someone@somewhere.com",
        "mobileNo":"someothernumber",
        "password":"$^^HFKH*"
      }
    }

  }
  """
  def printJson ={

    implicit val rltRds = (
      (__ \ "firstName").read[String] ~
      (__ \ "lastName").read[String] ~
      (__ \ "email").read[String] ~
      (__ \ "mobileNo").read[String] ~
      (__ \ "password").read[String]
    )(Retailer)    

    implicit val bsnsRds = (
      (__ \ "name").read[String] ~
      (__ \ "preferredUrl").read[String] ~
      (__ \ "businessPhone").read[String] ~
      (__ \ "retailer").read[Retailer](rltRds)
    )(Business)    


    val buisness = Json.parse(jsonValue).validate[Business](bsnsRds)
    val bus = new Business("Some Business","somebusinessurl","somenumber", new Retailer("Some","One","someone@somewhere.com","someothernumber","$^^HFKH*"))
    //val json = Json.toJson(bus)

    println(buisness)
  }   




  def main(args: Array[String]): Unit = {
    printJson
  }

}

当我尝试将json解析为Scala对象(在这种情况下为Business Class)时,出现Json验证错误.错误是

I get Json Validation Error when I try to parse the json into Scala object (Business Class in this case). The error is

JsError(List((/retailer,List(ValidationError(validate.error.missing-path,WrappedArray()))), (/preferredUrl,List(ValidationError(validate.error.missing-path,WrappedArray()))), (/name,List(ValidationError(validate.error.missing-path,WrappedArray()))), (/businessPhone,List(ValidationError(validate.error.missing-path,WrappedArray())))))

JsError(List((/retailer,List(ValidationError(validate.error.missing-path,WrappedArray()))), (/preferredUrl,List(ValidationError(validate.error.missing-path,WrappedArray()))), (/name,List(ValidationError(validate.error.missing-path,WrappedArray()))), (/businessPhone,List(ValidationError(validate.error.missing-path,WrappedArray())))))

但是,如果我的json是

However if my json is like

val jsonValue = """
    {
      "name":"Some Business Name",
      "preferredUrl":"someurl",
      "businessPhone":"somenumber",
      "retailer":
      {
        "firstName":"Some",
        "lastName":"One",
        "email":"someone@somewhere.com",
        "mobileNo":"someothernumber",
        "password":"$^^HFKH*"
      }
  }
  """

请注意,删除了外部括号"{"和"business:"键. 我得到一个JsSuccess.与第一种情况一样,我该如何写Json的读物? 另外,我该如何通用?

Note that the outer bracket "{" and the "business:" key are removed. I get a JsSuccess. How do I write the reads for the Json as in the first case? Also, how can I do it in a generic way?

请帮助.

推荐答案

只需在路径中添加business键:

 implicit val bsnsRds = (
      (__ \ "business" \ "name").read[String] ~
      (__ \ "business" \ "preferredUrl").read[String] ~
      (__ \ "business" \ "businessPhone").read[String] ~
      (__ \ "business" \ "retailer").read[Retailer](rltRds)
    )(Business)

这篇关于Scala Play Json阅读的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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