JSON在Django Rest API中使用POST解析错误 [英] Json parse error using POST in django rest api

问题描述

我正在尝试通过Django REST框架实现一个简单的GET/POST api

I am trying to implement a simple GET/POST api via Django REST framework

views.py

class cuser(APIView):
def post(self, request):
   stream  = BytesIO(request.DATA)
    json = JSONParser().parse(stream)
    return Response()

urls.py

from django.conf.urls import patterns, url
from app import views
urlpatterns = patterns('',

           url(r'^challenges/',views.getall.as_view() ),
           url(r'^cuser/' , views.cuser.as_view() ),
      )

我正在尝试POST一些json到/api/cuser/(api是项目的urls.py中的名称空间)， JSON

I am trying to POST some json to /api/cuser/ (api is namespace in my project's urls.py ) , the JSON

{
"username" : "abhishek",
"email" : "[e-mail]",
"password" : "secretpass"
}

我在Browseable API页面和httpie(类似于curl的python制作的工具)上都尝试过

I tried from both Browseable API page and httpie ( A python made tool similar to curl)

httpie command

http --json POST http://localhost:58601/api/cuser/ username=abhishek email=[e-mail] password=secretpass

但是我收到JSON解析错误:

but I am getting JSON parse error :

JSON parse error - Expecting property name enclosed in double quotes: line 1 column 2 (char 1)

Whole Debug message using --verbose --debug

    POST /api/cuser/ HTTP/1.1

Content-Length: 75

Accept-Encoding: gzip, deflate

Host: localhost:55392

Accept: application/json

User-Agent: HTTPie/0.8.0

Connection: keep-alive

Content-Type: application/json; charset=utf-8



{"username": "abhishek", "email": "[e-mail]", "password": "aaezaakmi1"}

HTTP/1.0 400 BAD REQUEST

Date: Sat, 24 Jan 2015 09:40:03 GMT

Server: WSGIServer/0.1 Python/2.7.9

Vary: Accept, Cookie

Content-Type: application/json

Allow: POST, OPTIONS



{"detail":"JSON parse error - Expecting property name enclosed in double quotes: line 1 column 2 (char 1)"}

推荐答案

您遇到的问题是您的请求已经被解析，并且您试图再次解析它.

The problem that you are running into is that your request is already being parsed, and you are trying to parse it a second time.

来自解析器如何确定"

视图的有效解析器集始终定义为类列表.当访问request.data时，REST框架将检查传入请求的Content-Type标头，并确定使用哪个解析器来解析请求内容.

The set of valid parsers for a view is always defined as a list of classes. When request.data is accessed, REST framework will examine the Content-Type header on the incoming request, and determine which parser to use to parse the request content.

在您的代码中，您正在访问request.DATA，它等同于request.data的2.4.x.因此，您的请求一被调用就被解析，而request.DATA实际上正在返回您希望解析的字典.

In your code you are accessing request.DATA, which is the 2.4.x equaivalent of request.data. So your request is being parsed as soon as you call that, and request.DATA is actually returning the dictionary that you were expecting to parse.

json = request.DATA

实际上就是解析传入的JSON数据所需的全部.您实际上是在将Python字典传递给json.loads，该字典似乎无法解析它，这就是为什么出现错误的原因.

is really all you need to parse the incoming JSON data. You were really passing a Python dictionary into json.loads, which does not appear to be able to parse it, and that is why you were getting your error.

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