Play2找不到我的隐式读取或JSON格式 [英] Play2 does not find my implicit Reads or Format for JSON
问题描述
这是我的搜索对象:
package models.helper
import play.api.libs.json.Format
import play.api.libs.json.JsValue
import play.api.libs.json.JsObject
import play.api.libs.json.JsString
case class Search (name: String, `type`:String){
implicit object SearchFormat extends Format[Search] {
def reads(json: JsValue): Search = Search(
(json \ "name").as[String],
(json \ "type").as[String]
)
def writes(s: Search): JsValue = JsObject(Seq(
"name" -> JsString(s.name),
"type" -> JsString(s.`type`)
))
}
}
我正在尝试使用WS调用Web服务时使用此类:
I'm trying ot use this class when calling a webservice using WS:
val search = response.json.as[Search]
但是scala编译器一直在抱怨这一行:
But the scala compiler keeps complaining on this line:
未找到用于model.helper.Search类型的Json反序列化器.尝试 为此类型实现隐式的Reads或Format.
No Json deserializer found for type models.helper.Search. Try to implement an implicit Reads or Format for this type.
有人可以告诉我我在做什么错吗?
Could anybody tell me what I'm doing wrong?
- 从 https://sites.google上获取示例. com/site/play20zh/scala-developers/working-with-json
- 该线程讨论了相同的问题,但没有给出解决方案,在哪个站点上的示例是什么? https://groups.google.com/forum/?fromgroups# !topic/play-framework/WTZrmQi5XxY
- got the example from https://sites.google.com/site/play20zh/scala-developers/working-with-json
- this thread discusses the same issue but gives no solution, what example on what site? https://groups.google.com/forum/?fromgroups#!topic/play-framework/WTZrmQi5XxY
推荐答案
实际上,该示例是错误的.您需要隐式Format[Search]
值在隐式范围内可用.
Indeed the example is wrong. You need your implicit Format[Search]
value to be available in the implicit scope.
在您的情况下,Format[Search]
被定义为类Search
的嵌套值,因此您只能从Search
的实例获取它.
In your case the Format[Search]
is defined as a nested value of the class Search
, so you can reach it only from an instance of Search
.
因此,您想要做的是在另一个地方定义它,而不必创建Search
的实例即可引用它,例如在Formats
对象中:
So, what you want to do is to define it in another place, where it could be referenced without having to create an instance of Search
, e.g. in a Formats
object:
object Formats {
implicit SearchFormat extends Format[Search] {
…
}
}
然后您可以按以下方式使用它:
Then you can use it as follows:
import Formats.SearchFormat
val search = response.json.as[Search]
您还可以通过在Search
类的伴随对象中定义Format[Search]
值来摆脱进口税.实际上,当Scala编译器需要给定类型的隐式值时,它会自动查找类型参数的伴随对象:
You can also get rid of the import tax by defining the Format[Search]
value in the companion object of the Search
class. Indeed the Scala compiler automatically looks in companion objects of type parameters when it needs an implicit value of a given type:
case class Search(name: String, `type`: String)
object Search {
implicit object SearchFormat extends Format[Search] {
…
}
}
然后,您无需导入即可使用它:
Then you can use it without having to import it:
val search = response.json.as[Search]
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