使用JQuery getJSON方法 [英] Using JQuery getJSON method

问题描述

我正在尝试使用JQuery getJSON函数插入JSON数据. REST查询是:

I am attempting to pase a a JSON data using the JQuery getJSON function. The REST query is:

http://query.yahooapis.com/v1/public/yql?q=select%20woeid%20from%20geo.places%20where%20text%20%3D%20%22london%22&format=json&jsoncallback=?

我用来解析数据"以获取WOEID值的脚本在下面似乎不起作用:

The script I'm using to parse 'data' to obtain the WOEID value doesnt seem to work below:

 $.getJSON("http://query.yahooapis.com/v1/public/yql?"+
                "q=select%20woeid%20from%20geo.places%20where%20text%20%3D%20%22"+
                "london"+
                "%22&format=json&jsoncallback=?",
        function(data){
  console.log("json: " + data);
  var datatmp = data;
          if(data.results[0]){
            var data = filterData(data.results.place[0]);
           }
         }
       );

有人可以说我在做什么错吗? 链接文本

Can anyone say what I'm doing wrong? link text

推荐答案

您的代码需要一些调整，这是更新版本:

Your code needed a few tweaks, here's an updated version:

$.getJSON("http://query.yahooapis.com/v1/public/yql?"+
      "q=select%20woeid%20from%20geo.places%20where%20text%20%3D%20%22"+
      "london"+
      "%22&format=json&jsoncallback=json",
      function(data){
          if(data.query.results){
              $.each(data.query.results.place, function(i, v) {
                  console.log("woeid #" + i + ": " + v["woeid"]);
              });
          }
      });​

results对象位于query下面，因此您需要首先进入该位置，上面的代码遍历返回的第一个位置的woeid并警告它们...这只是一个开始，不确定您要做什么最终想使用woeid，但是希望这可以帮助您入门. 您可以在此处看到上面的代码.

The results object is beneath query, so you need to go into there first, the above code iterates through the woeid's of the first place returned and alerts them...it's just a starter, not sure what you ultimately wanted to do with the woeid but hopefully this will get you started. You can see the above code working here.

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