通过ID从json文件中获取特定值 [英] get specific value from json file by Id

问题描述

我正在使用$ .get获取可以正常工作的JSON文件内容，当前我想过滤并获取ID为4(最后一个)的项目，我该怎么做? 在Jquery文档中，我没有找到任何提示... http://api.jquery.com/jquery.get/

Im using the $.get to get JSON file content which is working fine,currently I want to filter and get the item with Id 4 (the last one) ,how should I do that ? in the Jquery doc I didn't find some hint to it... http://api.jquery.com/jquery.get/

这是代码:

 $.get('tweets.json');

这是JSON文件内容

[
  {
   "id": 1,
   "tweet": "OMG, worst day ever, my BF @BobbyBoo dumped me",
   "usersMentioned": [
     {
      "id": 10,
      "username": "BobbyBoo"
     }
    ]
  },
  {
   "id": 2,
   "tweet": "OMG, best day ever, my BF came back to me"
  },
  {
   "id": 3,
   "tweet": "OMG, worst day ever, just don't ask"
  },
  {
   "id": 4,
   "tweet": "@BobbyBoo OMG...just OMG!",
   "usersMentioned": [
     {
      "id": 10,
      "username": "BobbyBoo"
     }
    ]
  }
]

更新

当我尝试以下内容时，我在then(function(tweets)中没有得到任何东西，tweets是空的 值entry4填充了正确的值...

Currenlty when I try the following I dont get anthing in the then(function (tweets) ,tweets is emtpy the value entry4 is filled with the correct value...

  $.get('profile.json').then(function (profile) {

    $('#profile-pre').html(JSON.stringify(profile));

     $.get('tweets.json', null, null, 'json')
        .then(function (response) {
           var entry4 =  response.filter(function (tweet) {
               return tweet.id === 4;
            })[0];
             return entry4 ;
        })



}).then(function (tweets) {

    $('#tweets-pre').html(JSON.stringify(tweets));

    var myFriend = $.get('friend.json');

    return myFriend
}).then(function (friend) {

推荐答案

那是

$.get('tweets.json',null,null,'json')
  .then(function(response){
    var iAmNumberFour = response.filter(function(tweet){
      return tweet.id === 4;
    })[0];
  });

添加了类型，因为如果您不传递正确的标题，jQuery将不会为您解析JSON.

Added the type since if you don't pass the right headers, jQuery won't parse the JSON for you.

$.get('profile.json').then(function(profile) {

  $('#profile-pre').html(JSON.stringify(profile));

  return $.get('tweets.json', null, null, 'json')
    .then(function(response) {
      var entry4 = response.filter(function(tweet) {
        return tweet.id === 4;
      })[0];
      return entry4;
    })

}).then(function(entry4) {

  $('#tweets-pre').html(JSON.stringify(tweets));

  var myFriend = $.get('friend.json');

  return myFriend
})

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