如何执行jsonb键的LIKE查询? [英] How can I perform a LIKE query for a jsonb key?

问题描述

我具有以下jsonb结构:

I have the following jsonb structure:

{'this': '1', 'this_that': '0', 'this_and_that': '5'}

如何选择包含LIKE运算符的行?

How do I select rows that contain a LIKE operator?

SELECT * FROM myjson WHERE j ? 'this_%'

返回0行...希望与'this_that'和'this_and_that'相匹配. (请注意:"_"后面的字符可能会有很大差异，因此我无法进行完全匹配.)

Returns 0 rows...was hoping it would match 'this_that' and 'this_and_that'. (Note: the characters following '_' will potentially vary greatly and therefore I am not able to do an exact match).

推荐答案

您的示例不起作用，因为在jsonb和text类型之间没有隐式强制转换.您可以强制执行强制转换:

Your example should not work because there are not implicit cast between jsonb and text types. You can enforce casting:

SELECT '{"this": 1, "this_that": 0, "this_and_that": 5}'::jsonb::text 
            like '%"this%';

这不是干净的解决方案.更好的方法是解压缩json，并使用横向联接对未解压缩的数据进行过滤

It is not clean solution. Some better is unpacking json, and filtering over unpacked data with lateral join

postgres=# SELECT key FROM  myjson, lateral jsonb_each_text(j) 
             WHERE key LIKE 'this\_%';
┌───────────────┐
│      key      │
╞═══════════════╡
│ this_that     │
│ this_and_that │
└───────────────┘
(2 rows)

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