当键是数字字符串时，使用jq从json获取数据 [英] Getting data from json using jq when key is numerical string

问题描述

我是jq的新手，在解析json时遇到问题

I am new to jq and facing an issue while parsing my json

我在这样的变量中存储了一个json

I have a json stored in a variable like this

temp='{ "1": { "my_name": "one" }, "2": { "my_name": "two" } }'

现在我需要获取其他两个条目的my_name值

Now I need to get the value of my_name for both other entries

我已经尝试过类似的事情

I have tried something like this

echo $temp | jq '.1' //out put 0.1
I was assuming to get { "my_name": "one" } 

类似地，我也获得了my_name值

And similarly to get my_name value I did

echo $temp | jq '.1.my_name' // Its output is giving me error

任何人都可以帮助确定我的语法有什么问题以及如何纠正它.

Can any one please help to identify what is wrong with my syntax and how can I correct it.

推荐答案

只是将数字解释为浮点数.您需要在明确地使用键字符串的上下文中使用它.

Just the number gets interpreted as a float. You need to use it in a context where it is unambiguously a key string.

echo "$temp" | jq '.["1"]["my_name"]'

和

echo "$temp" | jq '.["1"]'

获取包含的字典.

有了一个足够新的jq(我认为> = 1.4)，您还可以说

With a sufficiently new jq (I think >= 1.4) you can also say

echo "$temp" | jq '."1".my_name'

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