将C#泛型类型作为参数传递 [英] Pass C# generic type as a parameter
问题描述
我有一个声明为
public interface ISomething<T> where T : class
在界面的某处,我有一个成员声明为
and somewhere in the interface I have a member declared as
[JsonProperty("someProperty")]
[JsonConverter(typeof(ConcreteTypeConverter<List<T>>))]
List<T> SomePropertyList{ get; set; }
我在ConcreteTypeConverter<List<T>>
上收到一条错误消息,说它不能使用类型(T)作为参数.我的ConcreteTypeConverter类使用类型T并返回JSON反序列化所需的T的具体实现.这里的情况是T可以有大约20种不同的类型,但我想避免使用20个这样的接口-这就是为什么我选择了通用接口.
I get an error on ConcreteTypeConverter<List<T>>
saying it cannot use a type (T) as an argument. My ConcreteTypeConverter class takes a type T and returns a concrete implementation of T which is needed for JSON deserialization.The scenario here is that T can have about 20 different types.But I would like to avoid having 20 such interfaces - that's why I opted for a generic interface.
用法类似于
ISomething<SomeType> variable = new Something<SomeType>();
var list = variable.SomePropertyList;
其中SomeType是T的实际实现.在这种情况下是否可以使用泛型?
where SomeType is the actual implementation of the T. Is there any way to use generics in such a situation?
我的ConcreteConverterClass继承自JsonConverter(使用Newtonsoft.Json):
My ConcreteConverterClass derives from JsonConverter (using Newtonsoft.Json):
public class ConcreteTypeConverter<TConcrete> : JsonConverter
{
public override bool CanConvert(Type objectType)
{
return true;
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
serializer.Serialize(writer, value);
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
return serializer.Deserialize<TConcrete>(reader);
}
}
我的确切错误是:
Attribute Argument cannot use type parameters
推荐答案
如果SomePropertyList
不是具体类型,例如,
You only need the ConcreteTypeConverter
if SomePropertyList
is not a concrete type, e.g.
[JsonProperty("someProperty")]
[JsonConverter(typeof(ConcreteTypeConverter<List<T>>))]
IList<T> SomePropertyList{ get; set; }
如果这不是问题,只需将您的属性声明更改为
If this is not an issue, just change your property declaration to
[JsonProperty("someProperty")]
List<T> SomePropertyList{ get; set; }
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